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3 years ago

10

I need the answer fast pls

1 answer:

BaLLatris [955]3 years ago

7 0

the answer is the second graph (b) ^^

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Alicia is sewing a rectangle bedspread that measures 72 inches by 60 inches. The bedspread is red with a gold circle 18 inches i

Natalija [7]

Answer:

$4,066\ in^{2}$

Step-by-step explanation:

we know that

The area of the bedspread that is red is equal to the area of rectangle minus the area of the circle

step 1

Find the area of rectangle

The area is equal to

$A=72*60=4,320\ in^{2}$

step 2

Find the area of the circle

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ----> the radius is half the diameter

assume

$\pi=3.14$

substitute

$A=(3.14)(9)^{2}$

$A=254.34\ in^{2}$

step 3

Find the area of the bedspread that is red

Find the difference of the areas

$4,320\ in^{2}-254.34\ in^{2}=4,066\ in^{2}$

5 0

3 years ago

A population of rabbits is described by the function R(t) = 100(2t/5), where t is measured in months and R is measured in rabbit

Savatey [412]

Answer and Step-by-step explanation: The graph is shown in the attachment.

a. ΔR on [1,2] is mathematically expressed as:

ΔR = R(2) - R(1)

which means difference of population of rabbits after 2 months and after 1 month.

$R(1) = 100(\frac{2}{5}.1 )$

$R(1) = 100(\frac{2}{5} )$

R(2) = $100(\frac{2}{5}.2 )$

$R(2) = 100(\frac{4}{5} )$

$\Delta R = 100(\frac{4}{5} )-100(\frac{2}{5} )$

$\Delta R = 100[\frac{4}{5} - \frac{2}{5} ]$

$\Delta R=$ 40

Difference of rabbits between first and second months is 40.

b. R(0) = 100( $\frac{2}{5} .0$ )

R(0) = 0

Initially, there no rabbits in the population.

c. R(10) = $100(\frac{2}{5}.10 )$

R(10) = 400

In 10 months, there will be 400 rabbits.

d. R(t) = 500

$500=100(\frac{2}{5}.t )$

$\frac{500}{100}=\frac{2}{5}.t$

$t = \frac{500.5}{100.2}$

t = 12.5

In 12 and half months, population of rabbits will be 500.

3 0

3 years ago

Nasser is following this recipe to make flapjacks.

bogdanovich [222]

Nasser is making 80 flapjacks

1800g / 225g x 10=80

8 0

3 years ago

A square has a side length of 5x and a perimeter of 60.<br> What is the value of x?

kozerog [31]

Answer:

$x=3$

Step-by-step explanation:

$60/4=15\\15/5=3\\x=3$

7 0

3 years ago

A u.s. customs inspector decides to inspect 3 out of 16 shipments for contraband. find the probability that 2 out of the 3 shipm

xz_007 [3.2K]

There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.

There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%

_____
C(n,k) = n!/(k!(n-k)!)

8 0

3 years ago