Answer:
Step-by-step explanation:
I take it that this is some sort of ratio. Start by solving the brackets on the left.
Brackets: 1/3 - 1/10
Brackets: 10/30 - 3/30
Brackets: 7/30
Brackets^2: 49/900
Brackets^2 - 1/5: 49/900 - 180/900
Brackets^2 - 1/5: -131/900
(2/5)^2 = 4/25
The way this read, it should be

Which when you invert and multiply becomes

which finally becomes

Oh gosh oh I thought had the president of the
Answer:
Cos A = (√51)/ 10
Step-by-step explanation:
sin is opposite/hypothenuse
cos is adjacent/hypothenuse
Pythagorus theorem says that c² = a² + b²
10² = 7² + b²
b² = 100 - 49
b = ±√51
It doesn't make sense for a length to be a minus number therefore, we will use +√51.
Cos A = (√51)/ 10
Tell me if I am wrong.
Can I get brainliest
A pergunta não está bem formatada. No entanto, pelo que parece óbvio
Responda:
3 horas
Explicação passo a passo:
Fração de hora gasta por sessão = 3/4 horas por sessão
Se o exercício for feito apenas aos domingos
Número de domingos por mês = 4
Portanto, número de sessões = 4
Fração de horas por sessão * Número de sessões
3/4 * 4 = 3 horas
Portanto, 3 horas são dedicadas ao exercício por mês
1) -3(5x+2y=-3)⇒ -15x-6y=9
⇒ -9x=27
2(3x+3y=9)⇒ 6x+6y=18
2) -9x/-9=27/-9 ⇒ x=-3
3) 3(-3)+3y=9⇒ -9+9+3y=9+9⇒ 3y/3=18/3⇒ y=6
Answer: (-3,6)
Reasoning:
Step 1) In order to eliminate, first I had to multiple the first equation by -3 and the second by 2 so that when combining the equations y would cancel each other out so that I could solve for x. <em>Note: There are many combinations as to how you could multiple the equations so that either the x or y would cancel out.
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Step 2) Once y is eliminated, solve for x.
Step 3) Now plug x back into one of the original equations and solve for y. <em>Note: Plug x back into one of the original equations, not the equations that were changed by multiplication,</em>