Is 35 ,000.00 in the 30,000.00 to 40,000.00 range?

If we wanted to know how high a 5th-grade student could jump, how many students would be reasonable to test? 5, 12, 30, or 200.

77julia77 [94]

The right amount to test would be 30.

200 is to many kids and 12 is not enough.

Hope this Helps!!

4 0

3 years ago

Find the coordinates of the midpoint AB. 1) ( -2,4), (4,0) THANK YOU!! And it's worth a lot of points if I get it right.

AnnyKZ [126]

-2+4 is 2/2 is (1,y)
4+0 divided by 2 is 2
coordinate is (1,2)

3 0

4 years ago

A researcher classifies firefighters according to whether their gloves fit well or poorly and by gender. They want to know if th

snow_tiger [21]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the proportion of "X: gloves fitness, categorized: Fit poorly and Fit well" is the same for two populations of interest, "male firefighters" and "female firefighters"

To do this you have to conduct a Chi-Square test of Homogeneity.

In the null hypothesis you have to state that the proportion of the categories of the variable are the same for all the populations of interest.

Be

M: the firefighter is male

F: the firefighter is female

Y: represents the category that the gloves "fit poorly"

W: represents the category that the gloves "fit well"

The null hypothesis will be:

H₀: P(Y|M)=P(Y|F)=P(Y)

P(W|M)=P(W|F)=P(W)

H₁: At least one of the statements in the null hypothesis is false.

α: 0.01

To calculate the statistic under the null hypothesis you have to calculate the expected frequencies first:

$E_{ij}= O_{.j}*\frac{O_{i.}}{n}$

O.j= total of the j-column

Oi.= total of the i-row

n= total of observations

$E_{11}= 547*\frac{152}{586} = 141.88$

$E_{12}=39*\frac{152}{586}= 10.12$

$E_{21}= 547*\frac{434}{586} = 405.12$

$E_{22}= 39*\frac{434}{586} = 28.88$

$X^2= sum \frac{(O_{ij}-E_{ij})^2}{E_{ij}} ~~~X^2_{(r-1)(c-1)}$

r= number of rows (in this case 2)

c=number of columns (in this case 2)

$X^2_{H_0}= \frac{(132-141.88)^2}{141.88} +\frac{(20-10.12)^2}{10.12} +\frac{(415-405.12)^2}{405.12} +\frac{(19-28.88)^2}{28.88} = 13.95$

Using the critical value approach, you have to remember that this test is <em><u>always</u></em> one-tailed to the right, meaning that you'll have only one critical value from which the rejection region is defined:

$X^2_{(r-1)(c-1);1-\alpha }= X^2_{1;0.99}= 6.635$

The decision rule is then:

If $X^2_{H_0}$ ≥ 6.635, reject the null hypothesis.

If $X^2_{H_0}$ < 6.635, do not reject the null hypothesis.

The calculated value is greater than the critical value, the decision is to reject the null hypothesis.

So at a 1% level you can conclude that this test is significant. This means that the proportions of gloves fitness, categorized in "Fit poorly" and "Fit well" are different for the male and female firefighters populations.

I hope this helps!

3 0

3 years ago

Read 2 more answers

Join my zoom im bored the participent ID is 439667

iragen [17]

Answer:

ok

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please help me im stick on this algebra 2 question

timama [110]

Hi I’m Charles from the University of Alaska Mathematics Department. I have a degree in dentistry, chemistry, zoology, algebra, geometry and finally literature. Anyways I was very interested by your question so I took a look and saw that this indeed is a hard question. However when I look at it it doesnt look to bad but it could pose to be quite difficult. So assuming from the question I could tell that you need to define the square root untill you hit the zero degree of -2. But you could instead solve for negative externalities of the equations and then use the Calvin formula to solve this question. So ultimately the answer is A. I hope this helps!

3 0

3 years ago