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Anna35 [415]
3 years ago
11

What is an equation of the line that is perpendicular to y=−4/5x+3 and passes through the point (4, 12) ?

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
3 0
The slope of the given line is -4/5.  The line perpendicular to that line will have a slope that is the opposite reciprocal.  In other words, the perpendicular slope will be 5/4.  If it passes through (4, 12), we have an x and a y value to use in y=mx+b.  y is 12, x is 4, and we have a slope of 5/4.  Filling in accordingly: 12= \frac{5}{4}(4)+b and 12 = 5 + b.  So b = 7.  Rewriting with our new slope and b value, y= \frac{5}{4}x+7.  And there you go!
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Ghella [55]

Answer:

A(9) = -52

Step-by-step explanation:

The given sequence is :

A(n)=-4 -6(n-1)

We need to find the 9th term of the above sequence.

To find it, put n = 9 in the above sequence.

A(9) = -4 -6(9-1)

= -4-6(8)

= -4-48

= -52

Hence, the 9th term of the sequence is -52.

8 0
3 years ago
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bearhunter [10]
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4 0
3 years ago
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natima [27]

Answer:

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Step-by-step explanation:

The answer is 144 because 192 multiplied by 75% is 144.

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5 0
3 years ago
What is the value of b that satisfies the equation below <br> 3(b+4)-2(2b+3)=-4
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The answer is C.

Hope this helps.

3 0
3 years ago
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