The side of the square is (12x+52)/4=3x+13.
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Kepler's third law described the relation between semi-major axis (or average distance to the star) and
the orbital period (how long it takes to complete one lap) as follows:
a^3 / p^2 = constant
In the case of our Solar system the constant is 1
This means that, for this problem:
a^3 / p^2 = 1
p^2 = a^3
p = a^(3/2)
The semi major axis is given as 101 million km. We need to convert this into AU where 1 AU is approximately 150 million Km
101 million Km = (101x1) / 150 = 0.67 AU
Now, we substitute in the equation to get the orbital period as follows:
p = (0.67)^(3/2) = 0.548 earth years
To complete the square, you would add to both sides (8/2)^2 = (4)^2 = 16. So, the correct answer would be D.
Answer:
12 inches
Step-by-step explanation:
when you want to find the original side, you multiply the new side by the scale factor. In this case, 18 and 2/3. And with that you'll get 12 inches
