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Maksim231197 [3]
4 years ago
11

If the earth's differentiation were any different, it may have affected its gravitational pull and_________ . Both of these fact

ors were essential to creating our atmosphere.
A.) tectonic activity
B.) temperature
C.) heat transfer
Physics
2 answers:
nika2105 [10]4 years ago
4 0

Answer :

If the Earth's differentiation were any different, it may have affected its gravitational pull and tectonic activity.

The geological processes that resulted in change of interior structure of Earth is known as differentiation.

Tectonic Activity is the movement of tectonic plates in the earth crust which gives rise to the volcanic activities.

Therefore, tectonic activity such as volcanic activity are also essential to creating our atmosphere by participating in the various atmospheric cycles.

Hence, The correct answer is A.) Tectonic Activity

ser-zykov [4K]4 years ago
3 0
A- TECTONIC ACTIVITY

If the earth's differentiation were any different, it may have affected its gravitational pull and TECTONIC ACTIVITY. Both of these factors were essential to creating our atmosphere.

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Answer:

Zero

Explanation:

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where

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A 10 kg ball strikes a wall with a velocity of 3 m/s to the left. The ball bounces off with a velocity of 3 m/s to the right. If
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Answer:

The force is 272.73 newtons

Explanation:

We're going to use impulse-momentum theorem that states impulse is the change on the linear momentum this is:

\overrightarrow{J}=\overrightarrow{p}_{f}-\overrightarrow{p}_{i} (1)

Impulse is also defined as average force times the time the force is applied:

\overrightarrow{J}=\overrightarrow{F}_{avg}(\varDelta t) (2)

By (2) on (1):

\overrightarrow{F}_{avg}(\varDelta t)= \overrightarrow{p}_{f}-\overrightarrow{p}_{i}

solving for \overrightarrow{F}_{avg}:

\overrightarrow{F}_{avg}=\frac{\overrightarrow{p}_{f}-\overrightarrow{p}_{i}}{\varDelta t} (3)

We already know Δt is equal to 0.22 s, all we should do now is to find \overrightarrow{p}_{f}-\overrightarrow{p}_{i} and put on (3) (\overrightarrow{p_{i}} the initial momentum and \overrightarrow{p_{f}} the final momentum). Linear momentum is defined as \overrightarrow{p}=m\overrightarrow{v} , using that on (3):

\varDelta\overrightarrow{p}=m \overrightarrow{v_{f}}-m \overrightarrow{v_{i}} (4)

Velocity (v) are vectors so direction matters, if positive direction is the right direction and negative direction left \overrightarrow{v_{i}}=+3\, \frac{m}{s} and \overrightarrow{v_{f}}=-3\, \frac{m}{s} so (4) becomes:

\varDelta\overrightarrow{p}=m(-3\frac{m}{s}- (+3\frac{m}{s}))=-(10kg)(6\frac{m}{s})

\varDelta\overrightarrow{p}=-60\, \frac{mkg}{s} (5)

Using (5) on (3):

\overrightarrow{F}_{avg}=\frac{-60\, \frac{mkg}{s}}{0.22s}

F_{avg}=272.73N

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denpristay [2]

Answer:

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