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3 years ago

CO2 NaCl HCl These may all be classified as

Physics

2 answers:

Makovka662 [10]3 years ago

8 0

Answer:

D) compounds and pure substances.

Explanation:

Nataly_w [17]3 years ago

6 0

Gas because that’s what the periodic table says

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Calculate the force of gravity on the 1.2-kg mass if it were 1.9×107 m above earth's surface (that is, if it were four earth rad

Anettt [7]

Answer:

Force of gravity, F = 0.74 N

Mass of an object, m = 1.2 kg

Distance above earth's surface, $d=1.9\times 10^7\ m$

Mass of Earth, $M=5.97\times 10^{24}\ kg$

Radius of Earth, $r=6.37\times 10^6\ m$

We need to find the force of gravity above the surface of Earth. It is given by :

$F=G\dfrac{mM}{R^2}$

R = r + d

R = 25370000 m

$F=6.67\times 10^{-11}\times \dfrac{5.97\times 10^{24}\ kg\times 1.2\ kg}{(25370000\ m)^2}$

F = 0.74 N

So, the force of gravity on the object is 0.74 N. Hence, this is the required solution.

5 0

4 years ago

Study the image below. What interaction causes the water to spread as they pass through the rock opening?

Kamila [148]

I think is diffracton.

7 0

3 years ago

Read 2 more answers

A vessel of 0.25 m3 capacity is filled with saturated steam at 1500 kPa. If the vessel is cooled until 25% of the steam has cond

soldier1979 [14.2K]

Answer:

the final pressure is P=353.5 kPa and the heat lost by the system (heat transferred) is Q= -3614.7327 kJ ( negative sign means heat outflow)

Explanation:

since the steam is at saturated state at 1500 kPa , from tables of saturated steam

at P= 1500 kPa → specific volume v= 0.13225 m³/kg , ug=2593.3 kJ/kg

thus

m = V/v = 0.25 m³ / 0.13225 m³/kg = 1.89 kg

for condensation until 25% of steam, then mass of steam is

mg₂ = 0.25* 1.89 kg = 0.4725 kg

if we neglect the volume occupied by the liquid , then the steam occupies

v₂ = V/m = 0.25 m³ / 0.4725 kg =0.529 m³/kg

returning to the saturated steam table

at v₂=0.529 m³/kg → 353.5 kPa , uL₂= 584.1585 kJ/kg , ug₂= 2548.4965 kJ/kg

then from the first law of thermodynamics

ΔU= Q - W , but since V=constant , dV=0 and W=∫PdV =0

Q= ΔU

Q= (mg₂*ug₂+ml₂*uL₂) - (m*ug) = 1.89 kg* (0.25*2548.4965 kJ/kg + 0.75*584.1585 kJ/kg - 2593.3 kJ/kg) = -3614.7327 kJ

5 0

3 years ago

You are part of a mission to Mars and have been assigned the task of designing balloons for the purpose of carrying scientific i

melomori [17]

Answer:

The radius of the balloon is R= 0.974 m

Explanation:

Atmospheric density on the surface of mars ρ = 0.0154 kg/m³

Mass density of balloon σ 5 gm/m² = 0.005 kg/m²

Total mass of balloon M = density of balloon* surface area

The balloon is considered as sphere

Surface area of sphere is given by 4π R²

Mass of balloon is M =σ *4πR²

M= (0.005 kg/m²)*(4π R²)

Volume of balloon is given by $\frac{4}{3}$ πR³

Density of atmosphere of mass is given by

ρ = Mass of balloon/volume of balloon

=(0.005 kg/m²)*(4π R²)/ $\frac{4}{3}$ πR³

Re arranging R

R = $\frac{3*0.005 kg/m²}{ 0.0154 kg/m³}$

R = 0.974 m

The radius of the balloon is R= 0.974 m

3 0

4 years ago

A common way to measure the distance to lightning is to start counting, one count per second, as soon as you see the flash. Stop

AURORKA [14]

Answer:

d = 1.07 mile

Explanation:

The rationale for this method is that the speed of light is much greater than the speed of sound, the definition of speed in uniform motion is

v = d / t

d = v t

the speed of sound is worth

v = 343 m / s

Therefore, the speed of sound must be multiplied by time to do this, all the units must be in the same system, as the distance in miles is requested

v = 343 m/s (1mile/1609 m) (3600s/1 h) = 343 (2.24) = 767.4 mile/h

v = 343 m / s (1 mile / 1609 m) = 0.213, mile/ s

If the measured time is t = 5s we multiply it by the speed

we substitute

d = 0.213 5

d = 1.07 mile

If you want to calculate the speed, this method in general is not widely used, since you must know the distance where the lightning occurred, which is relatively complicated.

8 0

3 years ago