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katen-ka-za [31]
3 years ago
11

How many cells must be connected in series to give the 350 v a large catfish can produce?

Physics
1 answer:
victus00 [196]3 years ago
3 0
Each electrocyte can produce 110 mv.
110 m/V=0.110V
n(0.110)=350
n=3182 (rounded)
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The force of replusion between two like charged particles will increase if​
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The distance of separation is decreased

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A hydrogen atom in a galaxy moving with a speed of 6.65×106 m/???? away from the Earth emits light with a wavelength of 5.13×10−
Mumz [18]

Answer:

The observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m.

Explanation:

Given that,

The actual wavelength of the hydrogen atom, \lambda_a=5.13\times 10^{-7}\ m

A hydrogen atom in a galaxy moving with a speed of, v=6.65\times 10^6\ m/s

We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :

v=c\times \dfrac{\lambda_o-\lambda_a}{\lambda_a}

\lambda_o is the observed wavelength

\lambda_o=\dfrac{v\lambda_a}{c}+\lambda_a\\\\\lambda_o=\dfrac{6.65\times 10^6\times 5.13\times 10^{-7}}{3\times 10^8}+5.13\times 10^{-7}\\\\\lambda_o=5.24\times 10^{-7}\ m

So, the observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m. Hence, this is the required solution.

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A small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of
Gennadij [26K]

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E = \frac{mg}{q}

Here,

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Rearranging to find the charge,

q = \frac{mg}{E}

Replacing,

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Since the field is acting upwards the charge on the drop should be negative to balance it in air. The equation to find the number of electrons then is

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Here,

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Replacing,

n = \frac{3.002*10^{-12}}{1.6*10^{-19}}

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