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3 years ago

HELP DUE in 20 MIN m∠10 =

Mathematics

2 answers:

Novay_Z [31]3 years ago

8 0

Answer:

133°

Step-by-step explanation:

∠10 = 180° - ∠9
∠9 ≅ ∠6 ≅ ∠2 = 47°

∠10 = 180° - 47° = 133°

PIT_PIT [208]3 years ago

6 0

Answer:

Angle 1, 4, 5,7,10,12,13,15 : 133°

Angle 2,3,6,8,9,11,14,16 :47°

Step-by-step explanation:

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Find the value of x.round to the nearest tenth

Nata [24]

Answer:

$\displaystyle x \approx 8.2$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] SOHCAHTOA

[Right Triangles Only] sinθ = opposite over hypotenuse

Step-by-step explanation:

Step 1: Identify Variables

Angle θ = 23°

Opposite Leg = x

Hypotenuse = 21

Step 2: Solve for x

Substitute in variables [sine]: $\displaystyle sin(23^\circ) = \frac{x}{21}$
[Multiplication Property of Equality] Isolate x: $\displaystyle 21sin(23^\circ) = x$
Rewrite: $\displaystyle x = 21sin(23^\circ)$
Evaluate: $\displaystyle x = 8.20535$
Round: $\displaystyle x \approx 8.2$

7 0

3 years ago

Solve the following proportion for y.y/5 = 7/8Round your answer to the nearest tenth.

Vinvika [58]

The given proportion is expressed as

y/5 = 7/8

If we crossmultiply, it becomes

y * 8 = 7 * 5

8y = 35

y = 35/8

y = 4.375

Rounding to the nearest tenth,

y = 4.4

3 0

2 years ago

Birth weights at a local hospital have a Normal distribution with a mean of 110 oz and a standard deviation of 15 oz. The propor

monitta

Answer:

c. 0.136.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 110, \sigma = 15$