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Vikki [24]
3 years ago
5

The best unit for measuring the width of a textbook would be

Mathematics
1 answer:
trapecia [35]3 years ago
4 0
<span>The best unit for measuring the width of a textbook would be centimeters.
A millimeter is a very small unit, so there would be no point in measuring width. Meters is too long. Decameters is still too long, so centimeters would be perfect.
</span>
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Write the equation in vertext form<br><br> Vertex: (3,6) ; y-intercept: 2
olganol [36]
Y= a(x-3)^2+6
2= a(0-3)^2+6
2=a(-3)^2+6
2=a(9)+6
2-6=9a
-4=9a
-4/9=a

Therefore the equation in vertex form is
y = -4/9 (x-3)^2+6
8 0
3 years ago
Divide 85 into the ratio of 2:3:5
alukav5142 [94]
The actual amount that needs to be divided = 85
The ratio in which the amount needs to be divided = 2:3:5
Let us assume the common ratio to be = x
Then
2x + 3x + 5x = 85
10x = 85
x = 85/10
  = 8.5
Then
The ratio in which the number 85 will be divided = 2 * 8.5:3 * 8.5:5 * 8.5
                                                                             = 17:25.5:42.5
So from the above deduction we can see that the number 85 can be divided in the ratio 17:25.5:42.5
4 0
3 years ago
For any real number c, √² =<br> A. ²<br> B. cl<br> C. 1<br> D. C
aliina [53]

Answer:

answer D    ( if i interpreted your question correctly )

Step-by-step explanation:

Sqrt (c^2)  = √(c^2) = C

8 0
2 years ago
8 and 1/5 + 4 and 2/5=?
Leviafan [203]
12 and 3/5 hope this helped
4 0
3 years ago
6. Determine how each multiplication or
tangare [24]
A) 27, 81
b) -30,-15
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3 0
3 years ago
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