The time it takes light from a flash camera to reach a subject 6.0 meters across a room in scientific notation is 2.0 *10^-8 s.
<u>Explanation:</u>
<u>Given</u>
t=?
d=6m
v=3*10^8 m/s
we have, v=d/t
here t=d/v
t=6m/3*10^8 m/s
v=2*10^-8 m/s
The time it takes light from a flash camera to reach a subject 6.0 meters across a room in scientific notation is 2.0 *10^-8 s.
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This question involves the concepts of the equations of motion both in the horizontal motion and the vertical motion.
The rock hits "30.91 m" away from the base of the building.
First, we will calculate the time taken by the rock to reach the ground by applying the second equation of motion in vertical motion:
where,
h = height of the building = 30 m
vi = initial vertical speed = 0 m/s
t = time = ?
g = acceleration due to gravity = 9.81 m/s²
Therefore,
t = 2.47 s
Now, we will calculate the horizontal distance by analyzing horizontal motion. Ignoring the air friction, the horizontal motion will be uniform:
where,
s = horizontal distance = ?
v = horizontal speed = 12.5 m/s
Therefore,
<u>s = 30.91 m</u>
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Learn more about equations of motion here:
brainly.com/question/5955789?referrer=searchResults
Answer:
Work done = 5.8 × 10⁵ J (Approx)
Explanation:
Given:
Mass of the beam (m) = 425 kg
Distance (s) = 117 m
Acceleration (a) = 1.8 m/s²
Find:
Work done.
Computation:
⇒ Work done = Force × Displacement
⇒ Work done = Mass (Acceleration + Acceleration of gravity) × Displacement
⇒ Work done = 425 (1.8 + 9.81) × 117
⇒ Work done = 425 (11.61) × 117
⇒ Work done = 577,307.25
⇒ Work done = 5.8 × 10⁵ J (Approx)
Answer:
Explanation:
the putty (W = 2.3lb) strikes the block with velocity ( here h = 8.7ft):
V =
conservation of linear momentum gives (where W = 22lb):
since k = 4lb/in and there are two springs, the initial spring deflection is
δ = = 2.75in
conservation of energy gives (datum is the initial position of the block and we divide with 12 to get deflection in inches):
ΔT + ΔV + ΔV = 0