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Alexeev081 [22]
3 years ago
12

Bart runs up a 2.91 meters high flight of stairs at a constant speed in 2.15 seconds. If barts mass is 65.9kg determine the work

which he did and his power rating
Physics
1 answer:
Tanzania [10]3 years ago
6 0

Answer:

1879.33J

874.1W

Explanation:

Given parameters:

Distance covered  = 2.91m

Time taken  = 2.15s

Mass of Bart = 65.9kg

Unknown:

Work done  = ?

Power rating  = ?

Solution:

Here, the work done is related to the the potential energy in climbing this flight of stairs.

  Work done = Potential energy  = mgH

where m is the mass

           g is the acceleration due to gravity

           H is the height

Work done  = 65.9 x 9.8 x 2.91  = 1879.33J

Power is defined as the rate at which work is being done.

         Power = \frac{Work done }{time taken}

                     = \frac{1879.33}{2.15}

                      = 874.1W

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<h3>What is altitude?</h3>

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5 0
2 years ago
An undersea research chamber is spherical with an external diameter of 5.50 m . The mass of the chamber, when occupied, is 87600
dmitriy555 [2]

Answer:

the buoyant force on the chamber is F = 7000460 N

Explanation:

the buoyant force on the chamber is equal to the weight of the displaced volume of sea water due to the presence of the chamber.

Since the chamber is completely covered by water, it displaces a volume equal to its spherical volume

mass of water displaced = density of seawater * volume displaced

m= d * V , V = 4/3π* Rext³

the buoyant force is the weight of this volume of seawater

F = m * g = d * 4/3π* Rext³ * g

replacing values

F = 1025 kg/m³ * 4/3π * (5.5m)³ * 9.8m/s² = 7000460 N

Note:

when occupied the tension force on the cable is

T = F buoyant - F weight of chamber  = 7000460 N - 87600 kg*9.8 m/s² = 6141980 N

4 0
4 years ago
N iron nail is made up of particles. What is true about the particles?
kirill [66]
They stay in place and vibrate.
7 0
3 years ago
In which situation does the law of conservation of momentum apply?
zvonat [6]

As per Newton's II law we know that

F = \frac{dP}{dt}

rate of change in momentum is Net outside force on the object

now here we will have if net outside force will be zero

then we can say

F = 0 = \frac{dP}{dt}

so from above equation we can say

dP = 0

and hence we have

P = constant

so the correct answer will be

<em>3.) in the absence of outside forces</em>

7 0
3 years ago
A car traveling at 3.6 m/s accelerates at the rate of 0.71 m/s2 for an interval of 4.4 s. Find vf. Incorrect: Your answer is inc
alexandr1967 [171]

Answer:

vf = 6.724 m/s

Explanation:

Velocity: This an be defined as the rate of change of displacement. Velocity is a vector quantity, because it can be represented both in magnitude and direction. The S.I unit of velocity is m/s.

From newton's equation of motion,

vf = vi + at ......................................... Equation 1

Where vf = final velocity, vi = initial velocity, a = acceleration, t = time.

Given: vi = 3.6 m/s, a = 0.71 m/s²,  t = 4.4 s.

Substitute into equation 1

vf = 3.6+0.71(4.4)

vf = 3.6+3.124

vf = 6.724 m/s

Hence, vf = 6.724 m/s

8 0
3 years ago
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