It varies with container, temperature, pressure and amount of gas. But, the volume occupied by a gas at a fixed temperature and pressure remains constant which is 22.4 L for 1 mole at STP.
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Saturated hydrocarbons are generally unreactive except in the presence of high temperatures and oxygen.
Saturated hydrocarbons are called Alkanes. These compounds are generally unreactive, but when exposed to high temperatures and oxygen they react in a combustion reaction to produce Carbon Dioxide and Water. This reaction is very violent and spontaneous and explosions of household gas cylinders occur because of the spontaneity of this reaction.
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Al (1s²2s²2p⁶3s²3p¹) - 3e⁻ → Al³⁺ (1s²2s²2p⁶)
3s²3p¹
Answer is: 3,4
Chemical reaction: HNO₂ + NaOH → NaNO₂ + H₂O.
c₀(HNO₂) = 1,2 M = 1,2 mol/dm³.
c₀(NaNO₂) = 0,8 M = 0,8 mol/dm³.
V₀(HNO₂) = V₀(NaNO₂) = 1 dm³ = 1 L.
c₀(NaOH) = 0,5 M = 0,5 mol/dm³.
n₀(HNO₂)= 1,2 mol/dm³ · 1 dm³ = 1,2 mol.
n₀(NaNO₂) = 0,8 mol/dm³ · 1 dm³ = 0,8 mol.
V(NaOH) = 400 mL · 0,001 dm³/mL = 0,4 dm³.
n₀(NaOH) = c₀(NaOH) · V₀(NaOH).
n₀(NaOH) = 0,5 mol/dm³ · 0,4 dm³ = 0,2 mol.
n(HNO₂) = 1,2 mol - 0,2 mol = 1 mol.
n(NaNO₂) = 0,8 mol + 0,2 mol = 1 mol.
c(HNO₂) = 1 mol ÷ 1,4 dm³ = 0,714 mol/dm³.
c(NaNO₂) = 1 mol ÷ 1,4 dm³ = 0,714 mol/dm³.
pH = pKa + log (c(HNO₂) / c(NaNO₂)).
pH = 3,4 + log (0,714 mol/dm³ / 0,714 mol/dm³) = 3,4.
No, the density of an object does not depend on its size.
A piece of glass with a volume of 10 cm³ may have a mass of 27 g. Its density is
<em>D</em> = <em>m</em>/<em>V</em> = 27 g/10 cm³ = 2.7 g/cm³
A piece of the same type of glass with a volume of 20 cm³ will have a mass
of 54 g. Its density is
<em>D</em> = <em>m</em>/<em>V</em> = 54 g/20 cm³ = 2.7 g/cm³
Thus, density does not change with the size of an object. Density is an <em>intensive property</em>.
