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3 years ago

7x=5y , find the slope and the y-intercept of each line whose equation is given.

Mathematics

2 answers:

hichkok12 [17]3 years ago

7 0

7x=5y can be written as y=7/5 x
so the slope is 7/5
y-intercept =0

nadezda [96]3 years ago

4 0

Slope would be -7/5. The y intercept would be 5.

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6 people meet for a business lunch. Each person shakes hands once with each other person present. How many handshakes take place

CaHeK987 [17]

30 handhakes, you obviously dont shake your own hand do 6*5 =30

6 0

3 years ago

Find the slope of the line that contains the following points. r(-2, 4), s(6, -2)

tangare [24]

Finding the slope using two points:

The formula for slope is

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

In this case...

$y_{2} =-2\\y_{1} =4\\x_{2} =6\\x_{1} =-2$

^^^Plug these numbers into the formula for slope...

$\frac{-2 - 4}{6 - (-2)}$

$\frac{-6}{8}$

^^^Can be further simplified to...

$\frac{-3}{4}$

^^^This is your slope

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3 years ago

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Strike441 [17]

Answer:

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5 0

2 years ago

Find the A.P whose second term is 12 and 7th term exceeds the 4th by 15

Art [367]

The 2nd term exists 12 and 7th term exceeds the 4th by 15 exists AP : 7,12,17,....

<h3>How to estimate the arithmetic progression?</h3>

Given : The second term exists 12th and the 7th term exceeds the 4th term by 15

The formula of the nth term :

$$a_{n}=a+(n-1) d$

Where d exists a common difference

n be the number of terms

a be the first term

Substitute the value of n = 2

$$a_{2}=a+(2-1) d=a+d$

Let, the second term exists 12

So, a + d = 12 ..........(1)

Substitute the value of n = 7

$$a_{7}=a+(7-1) d=a+6 d$

Substitute n = 4

$$a_{4}=a+(4-1) d=a+3 d$

We are given that the 7th term exceeds the 4th term by 15

So, a+6d-a-3d = 15

3d = 15

d = 5

Substitute the value of d in (1)

So, a+5 = 12

a = 12-5

a = 7

AP : a,a+d,a+2d,.... = 5, 7+5, 7+2(5),....=7,12,17,....

Therefore, AP : 7,12,17,....

To learn more about arithmetic progression refer to:

brainly.com/question/24191546

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4 0

1 year ago

You have collected data about the fasting blood glucose (FBG) level of participants in your study. You are delighted to find tha

liberstina [14]

Answer:

Between 79.2 and 84.8.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 82, standard deviation of 2.8.

In what range would you expect to find the FBG of 68% of your study participants?

By the Empirical Rule, within 1 standard deviation of the mean, so:

82 - 2.8 = 79.2

82 + 2.8 = 84.8

Between 79.2 and 84.8.

8 0

2 years ago