Please help with number 10

Mathematics

1 answer:

Flura [38]3 years ago

3 0

Answer:

see below for a drawing
the area of one of the trapezoids is 20 units²

Step-by-step explanation:

No direction or other information about the desired parallelogram is given here, so we drew one arbitrarily. Likewise for the segment cutting it in half. It is convenient to have the bases of the trapezoids be the sides of the parallelogram that are 5 units apart.

The area of one trapezoid is ...

A = (1/2)(b1 +b2)h = (1/2)(3+5)·5 = 20 . . . . square units

The sum of the trapezoid base lengths is necessarily the length of the base of the parallelogram, so the area of the trapezoid is necessarily 1/2 the area of the parallelogram. (The area is necessarily half the area of the parallelogram also because the problem has us divide the parallelogram into two identical parts.)

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Mkey [24]

I will try to solve your system of equations.
3
x
−
4
y
=
2
;
9
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−
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y
=
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Step: Solve
3
x
−
4
y
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2
for x:
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y
+
4
y
=
2
+
4
y
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3
x
=
4
y
+
2
3
x
3
=
4
y
+
2
3
(Divide both sides by 3)
x
=
4
3
y
+
2
3
Step: Substitute
4
3
y
+
2
3
for
x
in
9
x
−
12
y
=
6
:
9
x
−
12
y
=
6
9
(
4
3
y
+
2
3
)
−
12
y
=
6
6
=
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6
+
−
6
=
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+
−
6
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Step-by-step explanation:

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