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JulsSmile [24]
2 years ago
8

Why are some graphs limited to the first quadrant?

Mathematics
2 answers:
Kay [80]2 years ago
8 0
Graphs limited to the first quadrant would have positive points only, for bith the x and y variables, which means there wouldnt be any points in any other quadrant.... in other words, plotted points with both variables being positive would stay within the first quadrant. hope this answers your question!!
max2010maxim [7]2 years ago
7 0
Because the numbers are positive (x,y), all of the other quadrants have negitive numbers (-x,-y) (-x,y) (x, -y)
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grin007 [14]

Answer:

1458/3456 = 27/64 (simplification)

cube root of 27/64 = 3/4

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9/16 multplied by 1024 = 576.

THIS IS THE REAL WORKING AND ANSWER

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4 0
3 years ago
If x=9 and y=−3, evaluate the following expression:4/x−yGive your answer as a fraction in its simplest form.​
qwelly [4]
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6 0
3 years ago
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3.3002x10^23 how can you solve this?
raketka [301]
<span> 16501 (10^23) • 16501/5000
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8 0
3 years ago
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Can you help me please
STALIN [3.7K]

Answer:

36

Step-by-step explanation:

Here we a given a rule

It say

x(y÷3)^2

And we are given the values of x and y as

x=4 and y = 9

Let us replace them in the rule we are provided with

4(9÷3)^2

Applying DMAS rule, which says, first Division ollowed by Multiplication addition and then subtraction .

We first divide 9 by 3

9÷3 = 3

Hence

4(9÷3)^2 = 4(3)^2

Now we square first

3^2 = 3 \times 3 = 9

4(3)^2 = 4 \times 9

4(3)^2 = 36

Hence our final answer will be 36

4 0
3 years ago
If the original length are multiple by 1/3 what are the new coordinates
Olenka [21]

Answer:

2

Step-by-step explanation:

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