Answer:
Please see attached image and all steps below for both parts
Step-by-step explanation:
Task 1
The following system of equations includes a linear equation and a quadratic one:

it can be solved by using substitution in the second equation of the variable "y" by the linear expression of the first equation:

and this product of two factors will e zero when either factor is zero, that is: when x = 0, or when x = 9 [to make zero the binomial(x - 9)]
There are two solutions: x = 0 and x = 9.
When we graph both expressions in the system, we see that the line intercepts the parabola at the points (0, 2) and (9, 11). See attached image.
Task 2
Part 1:
Let's pick 30 as a number larger than 25. 30 can be written as 40 - 10
So we can use:

to calculate its square.
Part 2:
let's choose a=9 and b=10 so we use:

The answer should be B if I am correct
4(y - 7) = 2y - 38
4y - 28 = 2y - 38
4y - 2y = -38 + 28
2y = -10
y = -5
You mulitply 25 by .2 to get 5 and you add that to 25 to get $30
P would equal 98 i believe because since you are dividing p by 7 you would have to do the reverse to get p by itself which would be p=14*7 or p=98