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arlik [135]
3 years ago
13

a father is 43 years old and his 2 children is 8 and 6 years old. how many years will the sum of the ages of the two children be

until they're twice the father's age?​
Mathematics
1 answer:
elena55 [62]3 years ago
7 0

Answer:

Step-by-step explanation:

29 years they are combined ages the same and if this goes up 2:1 ratio every year thereafter from age 43 then to change 29:43 to make double it is x 8 43 x 8= 344 and  29 x16=464. The ages never become double.

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mihalych1998 [28]

Answer:

Some of the prime factors are 1,2,4,5,10,20,-1,-.2,-4,-5,-10,-20, and since 5 is prime you can just start with 5 and 4

Step-by-step explanation:

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3 years ago
What is the distributive property of 15+21
Marysya12 [62]

Answer:105 thats with reducing to  

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                            then 15/1 x 21/3 then simplify

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5 0
3 years ago
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zalisa [80]

Answer:

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Step-by-step explanation:

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3 years ago
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ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?
kotykmax [81]

Answer:

cos(C) =\frac{40}{41}\\\\cos(C)=0.976

Step-by-step explanation:

To find the cos (C) we must use the cosine theorem.

The cosine theorem says that:

c^2 = a^2 +b^2 -2abcos(C)

In this case:

c=AB = 9

b=CA = 41

a=BC = 40

So

9^2 = 40^2 +41^2 -2(40)*(41)cos(C)

9^2- 40^2- 41^2 =-2(40)*(41)cos(C)

cos(C) = -\frac{9^2- 40^2- 41^2}{2(40)*(41)}

cos(C) =\frac{40}{41}\\\\cos(C)=0.976

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Alex777 [14]

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65-50=15

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7 0
3 years ago
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