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belka [17]
3 years ago
15

Let f be a function such that f "(x) = 6x + 8.

Mathematics
1 answer:
Korolek [52]3 years ago
3 0
F''(x) = 6x + 8
∫f''(x) = f'(x) = 3x^2 + 8x + c1
∫f'(x) = f(x) = x^3 + 4x^2 + c1x + c2

At point (0, -2),
c2 = -2

3x - y = 2
y = 3x - 3

f'(0) = 3
c1 = 3

Therefore, the required function is
f(x) = x^3 + 4x^2 + 3x - 2
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