Hello!
The graph y < -2/3x + 2 has a dotted line. That means that any points on the dotted line or not shaded, is not a solution to this inequality. Since we are given 4 choices, we can substitute those values into the given inequality to see if it is true.
A) (0, 2)
2 < -2/3(0) + 2
2 < 2, this is false.
B) (3, 0)
0 < -2/3(3) + 2
0 < -2 + 2
0 < 0, this is false.
C) (0, 0)
0 < -2/3(0) + 2
0 < 2, this is true.
D). (0, 3)
3 < -2/3(0) + 2
3 < 2, this is false.
To check if choice C) (0, 0) is true, we should look at the given graph.
Since (0, 0) is in the shaded area, and is not graphed on the dotted line, therefore, a solution to this linear inequality is C, (0, 0).
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See that remainder in the lower, right hand corner of this array? It's 2. That is the value of f(-2).
Answer:
4h^2-6h-7
Step-by-step explanation:

Answers:
a = -6/37
b = -1/37
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Explanation:
Let's start things off by computing the derivatives we'll need

Apply substitution to get

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.
The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero
a-6b = 0
a = 6b
At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)
-6a -b = 1
-6(6b) - b = 1 .... plug in a = 6b
-36b - b = 1
-37b = 1
b = -1/37
Use this to find 'a'
a = 6b
a = 6(-1/37)
a = -6/37