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3 years ago

I need a specific explanation of how to answer this

Mathematics

1 answer:

zimovet [89]3 years ago

5 0

A rectangle has two dimensions, width and length, and the area of it is their product.

since we know its area is 3x²-11x-4, then the two factors from that trinomial are the likely width and length, namely (3x + 1) (x - 4).

you can check them with FOIL.

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A box is to be made out of a 8 cm by 20 cm piece of cardboard. Squares of side length x cm will be cut out of each corner, and t

abruzzese [7]

Answer:

hi! im sorry if this is wrong, im gonna try my hardest.

V= 160

L= 240

W=34

sry this is prob wrong just wanted to help ;(

7 0

3 years ago

According to a survey, 60 % of the residents of a city oppose a downtown casino. Of these 60 % about 8 out of 10 strongly opp

katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

Step-by-step explanation:

(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino.

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

Probability that a radomly selected resident opposes the casino: P(A)

Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the probability that a radomly selected resident opposes the casino, P(A)

Probability = number of favorable outcomes / number of possible outcomes

P(A) is given as 60%, which in decimal form is 0.60

ii) Next, determine,the probability that a resident who opposes the casino strongly opposes it, P(B/A):

It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or intersection: P(A∩B).

So, you can use the definition of conditional probability:

P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

P(A∩B) = P(B/A)×P(A) = (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that a radomly selected resident who opposes the casino does strongly oppose the casino, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

8 0

3 years ago

At the city museum, child admission is $6.20 and adult admission is $9.90 . On Monday, three times as many adult tickets as chil

murzikaleks [220]

Can you please delete this. I have answered it wrong. Thanks

7 0

3 years ago

Solve the following equation 5x-15=50

denis-greek [22]

X=13 I say.................

5 0

3 years ago