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Akimi4 [234]
4 years ago
12

A 3.2-l volume of neon gas (ne) is at a pressure of 3.3 atm and a temperature of 330 k. the atomic mass of neon is 20.2 g/mol, a

vogadro's number is 6.022 × 1023 molecules/mol, and the ideal gas constant is r = 8.314 j/mol · k = 0.0821 l · atm/mol · k. the mass of the neon gas is closest to
Chemistry
1 answer:
nevsk [136]4 years ago
6 0
Answer is:  the mass of the neon gas is closest to 7.8 grams.<span>
</span>

<span>V(neon) = 3.2 L; volume.
T = 330 K; temperature of gas.
p = 3.3 atm; pressure of gas.
R = 0.08206 L·atm/mol·K; gas constant.
Ideal gas law: p·V = n·R·T.
n = p·V / R·T.
n(neon) = 3.3 atm · 3.2 L / 0.08206 L·atm/mol·K · 330 K.
n(Ne) = 0.389 mol; amount of substance.</span>

m(Ne) = n(Ne) · M(Ne).

m(Ne) = 0.389 mol · 20.2 g/mol.

m(Ne) = 7.878 g; mass of neon.

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If 2.19 mol
never [62]

Answer:

1370 °C

Explanation:

We can use the Ideal Gas Law and solve for T.

pV = nRT

Data:  

p = 8.12 atm

V = 36.41 L

n = 2.19

R = 0.082 06 L·atm·K⁻¹mol⁻¹

Calculations

\begin{array} {rcl}pV & = & nRT\\\text{8.12 atm} \times \text{36.41 L} & = & \rm\text{2.19 mol} \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times T\\295.6&=&0.1797T\text{ K}^{-1}\\T& = &\dfrac{294.9 }{\text{0.1797 K}^{-1}}\\\\ & = & \text{1645 K}\\\end{array}

T = (1645 - 273.15) °C = 1370 °C

The temperature of the sample is 1370 °C.

3 0
3 years ago
Draw a three-dimensional representation of the oxygen-bearing carbon atom in ethanol,
Lana71 [14]

Answer : The three-dimensional structure of ethanol is shown below.

Explanation :

The ethanol molecule is made up of 2 carbon atoms, 6 hydrogen atoms and 1 oxygen atom.

The 3D representation is shown by solid, dash and wedge bonds.

Dash lines shows that the molecules are behind the plane.

Wedge shows that the molecules are above or front of the plane.

Solid line shows that the molecules are present on the plane.

The three-dimensional structure of ethanol is shown below.

3 0
3 years ago
Which of the following is NOT true of electronegativity?
polet [3.4K]
Whats the "following"?
8 0
3 years ago
If 5 mol of oxygen gas effuses through an opening in 10 seconds, how long will it take for the same amount of hydrogen gas to ef
andrezito [222]

Answer:

B

Explanation:

Recall the law of effusion:

\displaystyle \frac{r_1}{r_2} = \sqrt{ \frac{\mathcal{M}_2}{\mathcal{M}_1} }

Because 5 mol of oxygen was effused in 10 seconds, the rate is 0.5 mol/s.

Let the rate of oxygen be <em>r</em>₁ and the rate of hydrogen be <em>r</em>₂.

The molecular weight of oxygen gas is 32.00 g/mol and the molecular weight of hydrogen gas is 2.02 g/mol.

Substitute and solve for <em>r</em>₂:

\displaystyle \begin{aligned} \frac{(0.5\text{ mol/s})}{r_2} & = \sqrt{\frac{(2.02\text{ g/mol})}{(32.00\text{ g/mol})}} \\ \\  r_2 & = \frac{0.5\text{ mol/s}}{\sqrt{\dfrac{(2.02\text{ g/mol})}{(32.00\text{ g/mol})}}} \\ \\ & = 2.0\text{ mol/s}\end{aligned}

Because there are 5 moles of hydrogen gas:

\displaystyle 5.0\text{ mol} \cdot \frac{1\text{ s}}{2.0\text{ mol}} = 2.5\text{ s}

In conclusion, it will take about 2.5 seconds for the hydrogen gas to effuse.

Check: Because hydrogen gas is lighter than oxygen gas, we expect that hydrogen gas will effuse quicker than oxygen gas.

6 0
3 years ago
Click on the event or events that led to the formulation of the cell theory
Alexandra [31]
So back in 1665 Robert hook was able to view cells and describe them along with pictures, the reason he was able to see cells was because the microscope was invented a bit before, which allowed him to think about things differently, he was looking at a cork and saw squared objects, these objects were cells, according to him.

So while the cork was the reason he discovers cells on it in the first place,
The microscope was what allowed him to do that

So it’s (HOOKE LOOKING AT A CORK)
And it’s (THE INVENTION OF THE MICROSCOPE)
8 0
3 years ago
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