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Murljashka [212]
3 years ago
14

The temperature that is equivalent to 95°F

Chemistry
1 answer:
lara [203]3 years ago
7 0

Answer:

35 degrees celcius

Explanation:

wow

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An experiment produced 0.10 g CO2, with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is t
Y_Kistochka [10]
Using the accepted density of CO2 at STP, we get the expected volume of the gas.
0.10 g / (1.96g/L) = 0.051 g

Calculating for the percent error:
%error =( |0.051 - 0.056| / 0.051 ) (100) = 9.80%

The percent error is 9.80%.
6 0
3 years ago
Which of these are examples of negative tropism? (Select all that apply.)
irina1246 [14]
Negative tropism is the growth or movement of an organism away from a stimulus. A common example that can be used to explain negative tropism is the shoot of the plants that grow against gravity
7 0
2 years ago
HELP!!!! A glass flask containing 100 milliliters of water is sealed with a rubber stopper and placed on a burner. After a while
kondor19780726 [428]

Answer: A closed system, because energy can enter or leave the container, but the water molecules cannot

Explanation:

Open system: In this system energy and matter both have access to their surroundings beyond the boundaries of system. .

Closed system :In this type system only energy has an access to its surroundings beyond the boundaries of system but not matter.

Isolated system:In this type system exchange of both energy and matter are restricted to move outside the boundaries of system.

According to question, the system given is a closed system because energy is transferred from the burner to glass flask and from the glass flask to the water (matter). But water molecules are only getting condensed on the inside surface of the flask that is exchange of matter beyond the boundaries of the system is restricted. Hence, closed system ,A closed system, because energy can enter or leave the container, but the water molecules cannot.

7 0
3 years ago
Which statements accurately describe Dmitri Mendeleev’s contributions to the development of the periodic table? Check all that a
Varvara68 [4.7K]

Answer:

  • <em><u>Mendeleev produced the first orderly arrangement of known elements.</u></em>

  • <em><u>Mendeleev used patterns to predict undiscovered elements.</u></em>

Explanation:

  • <u>Mendeleev produced the first orderly arrangement of known elements and used patterns to predict the undiscovered elements.</u>

        Those two statments are true.

For the time being there were some 62 known elements. Before Medeleev some schemes to order part of the elements were proposed, but Medeleev showed the relationship between the atomic mass and the properties of the elements (supports second choice). This arrangement is known as the periodic table.

More importantly, Mendeleev predicted correctly the existance and properties of unknown elements, which is his major contribution: he left blanket spaces which where gradually filled when new elements where discovered (this supports the fourth choice).

The first modern chemistry book was written by Antoine Lavoisier (this discards first option).

Mendeleev ordered the elements by increasing mass number (this discards third choice), which was corrected later by the scientist Henry Moseley, who ordered the elements by increasing atomic number (number of protons).

Isotopes were not known by Mendeleev times, so this discards the last option.

8 0
3 years ago
Read 2 more answers
Give the value of the quantum number ℓ, if one exists, for a hydrogen atom whose orbital angular momentum has a magnitude of 6√(
MakcuM [25]

Answer:

For this angular momentum, no quantum number exist

Explanation:

From the question we are told that

   The magnitude of the angular momentum is  L  = 6\sqrt{\frac{h}{2 \pi} }

The generally formula for Orbital angular momentum is mathematically represented as

           L  = \sqrt{(l * (l + 1)) } *  \frac{h}{2 \pi}

Where l is the quantum number

now  

We can look at the given angular momentum in this form as

      L  = 6\sqrt{\frac{h}{2 \pi} }    =  \sqrt{36}  * \sqrt{\frac{h}{2 \pi}} }

comparing this equation to the generally equation for Orbital angular momentum

     We see that there is no quantum number that would satisfy this equation

5 0
4 years ago
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