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harina [27]
2 years ago
13

What is the molecular formula of a compound that molecular mass of 54 g/mol and an empirical formula of C₂H₃? C₂H₃, C₄H₆, C₆H₉,

C₈H₁₂
Chemistry
1 answer:
Shkiper50 [21]2 years ago
5 0

Answer:

Molecular formula = C₄H₆

Explanation:

Given data:

Molecular mass of compound = 54 g/mol

Empirical formula = C₂H₃

Molecular formula = ?

Solution:

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass = 12×2 + 3×1 = 27 g/mol

n = 54 / 27

n = 2

Molecular formula = n (empirical formula)

Molecular  formula = 2(C₂H₃)

Molecular formula = C₄H₆

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Answer:

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Ionic radius = 109 pm.

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First ionization energy = 410 kJ/mol

Explanation:

Hello!

In this case, since electronegativity, ionic radius, atomic radius and first ionization energy are periodic properties that have specific trends, we can summarize it by realizing that oxygen and beryllium belong the same period 2 and differ in group, 6A and 2A respectively.

In such a way, the required comparison is written below:

Electronegativity = 3.44 (oxygen) - 1.57 (beryllium) = 1.87.

Ionic radius = 140 pm (oxygen)- 31 pm (beryllium) = 109.

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First ionization energy = 1310 kJ/mol (oxygen) - 900 kJ/mol (beryllium) = 410 kJ/mol

It means that electronegativity, ionic radius and first ionization energy increases from left to right whereas the atomic radius from right to left.

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7 0
3 years ago
If a reaction has a theoretical yield of 10.0 g and a student does the reaction and
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6 0
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