The answer would be 28x right?
n < 0, is another way to say "n is negative", so let's check
![\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a^n~\hspace{10.5em}\stackrel{n = -n}{a^{-n}}\implies \cfrac{1}{a^n} \\\\\\ a^{-n}~\hspace{10em}\stackrel{n=-n}{a^{-(-n)}}\implies a^{+n}\implies a^n](https://tex.z-dn.net/?f=%20%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bnegative%20exponents%7D%0A%5C%5C%5C%5C%0Aa%5E%7B-n%7D%20%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5En%7D%0A%5Cqquad%20%5Cqquad%0A%5Ccfrac%7B1%7D%7Ba%5En%7D%5Cimplies%20a%5E%7B-n%7D%0A%5Cqquad%20%5Cqquad%0Aa%5En%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5E%7B-n%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0Aa%5En~%5Chspace%7B10.5em%7D%5Cstackrel%7Bn%20%3D%20-n%7D%7Ba%5E%7B-n%7D%7D%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5En%7D%0A%5C%5C%5C%5C%5C%5C%0Aa%5E%7B-n%7D~%5Chspace%7B10em%7D%5Cstackrel%7Bn%3D-n%7D%7Ba%5E%7B-%28-n%29%7D%7D%5Cimplies%20a%5E%7B%2Bn%7D%5Cimplies%20a%5En%20)
The equation for total operating costs is incorrect, then the answer is False. The total operating cost is the summation of the two components namely fixed costs and variable costs. Therefore, the equation of total operating costs should be the same as shown below:
Operating costs=fixed costs+variable costs
Answer:
<h2>Since log 3 = 0.4771 and log 10 = 1, so the characteristic of log 3 is 0 and the mantissa of log 10 is 0.</h2>
Step-by-step explanation:
<h2>
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Answer:
10
Step-by-step explanation:
Ground level is where h = 0, so solve the equation ...
h(x) = 0
-5(x -4)^2 +180 = 0 . . . . substitute for h(x)
(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36
x -4 = 6 . . . . . . . . . . . . . . positive square root*
x = 10 . . . . . . add 4
The object will hit the ground 10 seconds after launch.
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* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.