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jok3333 [9.3K]
3 years ago
11

In a bus there is, A pregnant lady 24 years old A security guard 37 years old A random woman 56 years old Driver 68 years old Wh

o is the youngest?
Mathematics
2 answers:
GREYUIT [131]3 years ago
7 0

hahha funny the baby of course

Scilla [17]3 years ago
4 0

Answer:

The baby

Step-by-step explanation:

If you count the baby inside the pregnant woman, then he is the youngest.

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Angie is thinking of a number that is divisible by both 8 and 12. What is the smallest number that Angie could be thinking of?
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Answer:

24

Step-by-step explanation:

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So yea just help this is the last one
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C Because thats the only thing there is no doubt

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3 years ago
y=c1e^x+c2e^−x is a two-parameter family of solutions of the second order differential equation y′′−y=0. Find a solution of the
vagabundo [1.1K]

The general form of a solution of the differential equation is already provided for us:

y(x) = c_1 \textrm{e}^x + c_2\textrm{e}^{-x},

where c_1, c_2 \in \mathbb{R}. We now want to find a solution y such that y(-1)=3 and y'(-1)=-3. Therefore, all we need to do is find the constants c_1 and c_2 that satisfy the initial conditions. For the first condition, we have:y(-1)=3 \iff c_1 \textrm{e}^{-1} + c_2 \textrm{e}^{-(-1)} = 3 \iff c_1\textrm{e}^{-1} + c_2\textrm{e} = 3.

For the second condition, we need to find the derivative y' first. In this case, we have:

y'(x) = \left(c_1\textrm{e}^x + c_2\textrm{e}^{-x}\right)' = c_1\textrm{e}^x - c_2\textrm{e}^{-x}.

Therefore:

y'(-1) = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e}^{-(-1)} = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e} = -3.

This means that we must solve the following system of equations:

\begin{cases}c_1\textrm{e}^{-1} + c_2\textrm{e} = 3 \\ c_1\textrm{e}^{-1} - c_2\textrm{e} = -3\end{cases}.

If we add the equations above, we get:

\left(c_1\textrm{e}^{-1} + c_2\textrm{e}\right) + \left(c_1\textrm{e}^{-1} - c_2\textrm{e}  \right) = 3-3 \iff 2c_1\textrm{e}^{-1} = 0 \iff c_1 = 0.

If we now substitute c_1 = 0 into either of the equations in the system, we get:

c_2 \textrm{e} = 3 \iff c_2 = \dfrac{3}{\textrm{e}} = 3\textrm{e}^{-1.}

This means that the solution obeying the initial conditions is:

\boxed{y(x) = 3\textrm{e}^{-1} \times \textrm{e}^{-x} = 3\textrm{e}^{-x-1}}.

Indeed, we can see that:

y(-1) = 3\textrm{e}^{-(-1) -1} = 3\textrm{e}^{1-1} = 3\textrm{e}^0 = 3

y'(x) =-3\textrm{e}^{-x-1} \implies y'(-1) = -3\textrm{e}^{-(-1)-1} = -3\textrm{e}^{1-1} = -3\textrm{e}^0 = -3,

which do correspond to the desired initial conditions.

3 0
3 years ago
Ms Steward is training for an IronMan Competition. She is determined to shatter every record ever known. She bikes, runs and swi
7nadin3 [17]

Answer:

912.9 miles total

Step-by-step explanation:

75.4 miles biking x 8 times =  603.2 miles in biking

22.4 miles running x 3 days =  67.2 miles in running

27.5 miles running x 5 days =  137.5 miles running (2nd)

15 miles swimming x 7 days =  105 miles swimming

603.2+67.2+137.5+105 =

912.9 miles total

5 0
3 years ago
I need help with this ​
pentagon [3]
All you have to do is cross multiply!

Ur answer to the first one is 9/10

Ur answer to the second ine is 4/5
3 0
3 years ago
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