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Tju [1.3M]
3 years ago
6

What is the probability that a point chosen at random in the given figure will be inside the larger square and outside the small

er square?
Enter your answer, as a fraction in simplest form, in the box.
P(inside larger square and outside smaller

Mathematics
2 answers:
In-s [12.5K]3 years ago
5 0

Answer:

P(inside larger square and outside smaller) = \frac{51}{100}

Step-by-step explanation:

Probability is the result of the division of the number of possible outcome by the number of an event.

In the question, for a point chosen, the point can be in the small square only or in the area or region between the small square and the big square as such,

Area of larger square = area of region between both squares + area of smaller square

Where the area of a square is S × S where S is the side of a square

Area of larger square = 10 × 10

                                    = 100 cm square

Area of smaller square = 7 × 7

                                      = 49 cm square

Area of the region between  both squares

                                      = 100 - 49

                                      = 51 cm square

The probability that a dot selected is inside the larger square and outside the smaller is

P(inside larger square and outside smaller) = Area of region between both square/ Area of larger square

P(inside larger square and outside smaller) = \frac{51}{100}

vodomira [7]3 years ago
5 0

Answer:

51/100

I hope its right

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A door delivery florist wishes to estimate the proportion of people in his city that will purchase his flowers. Suppose the true
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99.74% probability that the sample proportion will be less than 0.1

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

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Normal probability distribution

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

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So

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What is the probability that the sample proportion will be less than 0.1

This is the pvalue of Z when X = 0.1*276 = 27.6. So

Z = \frac{X - \mu}{\sigma}

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99.74% probability that the sample proportion will be less than 0.1

5 0
4 years ago
4. Charlie drove from Calgary to Saskatoon, which is a distance
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Answer:

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4 0
3 years ago
The time t required to drive certain distance varies inversely with the speed r. It takes 2 hours to drive the distance at 40 mi
Roman55 [17]

Answer:

\frac{16}{9}  hours

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Now, secondly, we have r = 45 and k = 80, we need to find t:

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4 0
3 years ago
I cannot figure this out. Any help would be appreciated.
Lesechka [4]
So you are finding M
90+x+15+3x+15=180
4x=60
X = 15
LMN = 15+15
LMN = 30
hopefully this is correct :)
7 0
2 years ago
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