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Tju [1.3M]
3 years ago
6

What is the probability that a point chosen at random in the given figure will be inside the larger square and outside the small

er square?
Enter your answer, as a fraction in simplest form, in the box.
P(inside larger square and outside smaller

Mathematics
2 answers:
In-s [12.5K]3 years ago
5 0

Answer:

P(inside larger square and outside smaller) = \frac{51}{100}

Step-by-step explanation:

Probability is the result of the division of the number of possible outcome by the number of an event.

In the question, for a point chosen, the point can be in the small square only or in the area or region between the small square and the big square as such,

Area of larger square = area of region between both squares + area of smaller square

Where the area of a square is S × S where S is the side of a square

Area of larger square = 10 × 10

                                    = 100 cm square

Area of smaller square = 7 × 7

                                      = 49 cm square

Area of the region between  both squares

                                      = 100 - 49

                                      = 51 cm square

The probability that a dot selected is inside the larger square and outside the smaller is

P(inside larger square and outside smaller) = Area of region between both square/ Area of larger square

P(inside larger square and outside smaller) = \frac{51}{100}

vodomira [7]3 years ago
5 0

Answer:

51/100

I hope its right

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Step-by-step explanation:

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A painter uses 1.2 liters of the paint to cover 1m2 of the wall. How much paint will he need to cover 0.5m2?
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Answer:

0.6 liters paint will he need to cover 0.5 m^2

Step-by-step explanation:

Direct Variation states that the two quantities are related in such a way that  increase in one quantity results in a corresponding increase in the other quantity and vice versa, then such type of a variation is called a direct variation.

i.e y\propto x

It is given that the painter uses 1.2 liters of paint to cover 1 m^2

This is the situation of Direct Variation:  As less area cover, less liters of paint.

Let two quantities are x  and y;

x represents the area covered by painter

y represents the liters uses by the painter.

Then, the ratio of any two values of y is equal to the corresponding value of x.

i.e,

\frac{y_{1}}{y_{2}} =\frac{x_{1}}{x_{2}} or

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therefore, from the given information we have;

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