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Slav-nsk [51]
3 years ago
7

The image of (6. – 9) after a dilation with respect to the origin is (4,-6). What is the scale factor

Mathematics
1 answer:
qaws [65]3 years ago
3 0

Answer:2/3 or .666666

Step-by-step explanation:

The dilation is a contraction

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Angle a is one ninth as large as its complement angle b
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The inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y
Cerrena [4.2K]

We have been given that the inverse variation y=\frac{3\times 10^8}{x} shows the relationship between wavelength in meters, x, and frequency, y. We are asked to find the wavelength for radio waves with frequency 3\times 10^9.

To find the required wavelength, we substitute y=3\times 10^9 in our given equation and solve for x as:

3\times 10^9=\frac{3\times 10^8}{x}

x=\frac{3\times 10^8}{3\times 10^9}

We can see that both numerator and denominator has 3, so we can cancel it out.

x=\frac{1\times 10^8}{1\times 10^9}

Using quotient rule of exponents \frac{a^m}{a^n}=a^{m-n}, we will get:

x=1\times 10^{8-9}

x=1\times 10^{-1}

Therefore, the wavelength for radio waves would be 1\times 10^{-1} meters and option B is the correct choice.

3 0
3 years ago
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7 0
3 years ago
Some liquid will be poured from a 16 ounce container until it is filled to the percent of the the larger container (87.5%).How m
4vir4ik [10]

Answer:

16 ounces

Step-by-step explanation:

First we are told that a container has a capacity of 16 ounces of liquid and therefore 16 ounces of liquid can fill that one container

The 16 ounces liquid from the 16 ounce container is fully emptied in a larger container and fills 87.5% of the larger container therefore the larger container is:

100/87.5×16 ounces= 18.285 ounces in liquid capacity

Therefore to fill the smaller 16 ounce container, the larger container would have to pour 16 ounces of liquid into the smaller container, and would would still have 18.285-16=2.285 ounces if it(the larger container) were filled to the brim(100%)

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3 years ago
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= (tan B/2)  / ( 2 + 3 sin²B/cos²B )=
= (sin B / cos B) / (( 2cos² B+3sin²B)/cos²B)=
=( sin B cos B ) / ( 2 cos²B + 3 ( 1 - cos² B ) ) =
= (sin B cos B ) / ( 2 cos² B + 3 - 3 cos² B ) =
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= ( sin 2 B ) / ( 5 - ( cos² B - sin² B ) ) =
= ( sin 2 B ) / ( 5 - cos 2 B )  - correct 
8 0
3 years ago
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