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3 years ago

Find the slope of the line passing through the points (1, -5) and (4, 1).

Mathematics

1 answer:

wlad13 [49]3 years ago

7 0

The slope of line passing through the points (1, -5) and (4, 1) is 24

Step-by-step explanation:

Slope is the steepness of a line passing through given points

Given points are:

(x1,y1) = (1, -5)

(x2,y2) = (4,1)

The slope is denoted by m. The formula for slope is:

$m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{1-(-5)}{4-1}\\=\frac{6}{3}\\=2$

The slope of line passing through the points (1, -5) and (4, 1) is 2

Keywords: Slope, Calculation of slope

Learn more about slope at:

#LearnwithBrainly

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Answer:

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Step-by-step explanation:

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Simplified is $0.02

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Solve the following system of equations. Write each of your answers as a fraction reduced to lowest terms. In other words, write

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Answer:

x = 57/28

y = -95/84

z = 97/168

Step-by-step explanation:

Use the application in the next link: https://www.zweigmedia.com/RealWorld/tutorialsf1/scriptpivotold.html

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then using the tool provided, make row operations until you find the solution:

r2 = r2-3r1

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r3 = r3+2r1

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r2 = r2*(-1/13)

$\left[\begin{array}{cccc}1&5&8&1\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]$

r1 = r1- r2*5

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]$

r3 = r3+ r2*-3

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&168/13&97/13\\\end{array}\right]$

r3 = r3*13/168

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&1&97/168\\\end{array}\right]$

r2 = r2- r3*22/13

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]$

r2 = r2+ r3*6/13

$\left[\begin{array}{cccc}1&0&0&57/28\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]$

Here you have a reduced array an therefore the answers to each variable are on each row:

$\left[\begin{array}{c}x\\y\\z\end{array}\right]$

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blsea [12.9K]

Answer:

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Harrizon [31]

We know that the volume of a sphere of radius r is given by

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Substituting the value of volume in the above equation, we get

$4,188.79=\frac{4}{3}\pi r^3\\
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r^3=1000\\
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Now, the final volume is given by 14,137.167 cubic centimeters. Thus, we have

$14137.167 =\frac{4}{3}\pi r^3\\
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4\pi r^3=14137.167 \times 3\\
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r^3=\frac{14137.167\times 3}{4\pi}\\
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Now, let us find the surface areas for these two radii.

For $r=10$

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$S=4\pi r^2\\
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Similarly, for

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Therefore, the increase in the surface area is given by

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Hence, the average rate at which the surface area is changing is given by

$\frac{1570}{12}=130.8$

Therefore, the average rate at which the surface area is changing is given by 130.8 square centimeters per second.

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