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2 years ago

Find the slope of the line passing through the points (1, -5) and (4, 1).

Mathematics

1 answer:

wlad13 [49]2 years ago

7 0

The slope of line passing through the points (1, -5) and (4, 1) is 24

Step-by-step explanation:

Slope is the steepness of a line passing through given points

Given points are:

(x1,y1) = (1, -5)

(x2,y2) = (4,1)

The slope is denoted by m. The formula for slope is:

$m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{1-(-5)}{4-1}\\=\frac{6}{3}\\=2$

The slope of line passing through the points (1, -5) and (4, 1) is 2

Keywords: Slope, Calculation of slope

Learn more about slope at:

#LearnwithBrainly

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Express each percent as a fraction or mixed number in simplest form.

kari74 [83]

Answer:

120/100

Step-by-step explanation:

120÷20= 6

100÷20=5

6/5 = 1⅕

6 0

2 years ago

Which pair of angles are vertical angles?

Irina-Kira [14]

Answer:

Option 4.∠ERT and ∠MRC

Step-by-step explanation:

Definition of vertical angles : The angles opposite each other when two lines cross. They are always equal.Vertical" refers to the vertex (where they cross).They are also called vertically opposite angles.

Option 1. ∠KRC and ∠CRH

Refer the figure .

These angles does not satisfy the definition of vertical angles . since these angles are not opposite.

Option 2. ∠KRE and ∠ERT

These angles does not satisfy the definition of vertical angles . since these angles are not opposite.

Option 3. ∠MRC and ∠KRM

These angles does not satisfy the definition of vertical angles . since these angles are not opposite.

Option 4.∠ERT and ∠MRC

MT and EC are the two lines that cross each other at vertex R ,

Thus ∠ERT and ∠MRC are opposite to each other .

Hence ∠ERT and ∠MRC are pair of vertcal angles .

3 0

2 years ago

Read 2 more answers

You have drawn a simple random sample of 36 college students, asking each student how much rent they pay per month. You obtain a

Karo-lina-s [1.5K]

Answer:

$573-1.690\frac{22}{\sqrt{36}}=566.8033$

$573+1.690\frac{22}{\sqrt{36}}=579.1967$

And the 90% confidence interval would be between [566.80 and 579.20]

Step-by-step explanation:

Information given

$\bar X=573$ represent the sample mean

$\mu$ population mean (variable of interest)

s=22 represent the sample standard deviation

n=36 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=36-1=35$

The Confidence level is 0.90 or 90%, the significance would be $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value for this case would be $t_{\alpha/2}=1.690$