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3 years ago

6

20) A company made $4500 in profit and reserved $90 for training staff. What percentage of the profit, does the company reserve

for training?

1 answer:

kotegsom [21]3 years ago

7 0

Answer:

2%

Step-by-step explanation:

the amount reserved in % is ($90÷$4500)×100=2%

so the $90 since is the amount you need to divide by the actual profits

and multiply by 100 for you to get the amount in %

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If ∆ABC = ∆EDF where the coordinates of A(0,2), B(2,4), and C(2,-1), what is the measure of DF?A-3B-3.1C-5D-5.9Please respond qu

aev [14]

The triangles ABC and EDF are congruent, meaning they have the same side lengths and angles measures.

The measure of DF, as both triangles are congruent, is equal to the measure of BC.

We can calculate the length of BC using the distance formula:

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As BC is congruent with DF and BC=5, the length of DF is 5 units.

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3 years ago

What is the sign of 3x y3xy3, x, y when x>0x>0x, is greater than, 0 and y<0y<0y, is less than, 0?

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4 years ago

Read 2 more answers

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

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3 years ago

Svetradugi [14.3K]

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3 years ago