1/2.54 = 90/x
Cross multiply
(1)x = (2.54)(90)
x would equal 228.6
The answer would be 90 in/ 228.6 cm.
5x-7y=14
-5x -5x
^
Subtract 5x from both sides
-7y=-5x+14
Divide by -7 by all of the numbers
y=-5/7x-2
Answer:
There are 35990 ways in which 2 or 3 nodes fail
Step-by-step explanation:
Given : A computer network has 60 switching nodes.
To Find : In how many ways can 2 or 3 nodes fail?
Solution:
We are supposed to find no. of ways can 2 or 3 nodes fail.
So, we will use combination here .
No. of ways can 2 or 3 nodes fail=![^{60}{C_2 +^{60}C_3](https://tex.z-dn.net/?f=%5E%7B60%7D%7BC_2%20%2B%5E%7B60%7DC_3)
Formula : ![^nC_r =\frac{n!}{r!(n-r)!}](https://tex.z-dn.net/?f=%5EnC_r%20%3D%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D)
No. of ways can 2 or 3 nodes fail=![\frac{60!}{2!(60-2)!}+\frac{60!}{3!(60-3)!}](https://tex.z-dn.net/?f=%5Cfrac%7B60%21%7D%7B2%21%2860-2%29%21%7D%2B%5Cfrac%7B60%21%7D%7B3%21%2860-3%29%21%7D)
=![35990](https://tex.z-dn.net/?f=35990)
Hence there are 35990 ways in which 2 or 3 nodes fail