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sergey [27]
3 years ago
15

Solution set for 6a^2-a-5=0

Mathematics
2 answers:
UNO [17]3 years ago
7 0
6a^2-a-5=0\\\\6a^2+5a-6a-5=0\\\\a(6a+5)-1(6a+5)=0\\\\(6a+5)(a-1)=0\iff6a+5=0\ \vee\ a-1=0\\\\6a+5=0\ \ |-5\\6a=-5\ \ \ |:6\\a=-\dfrac{5}{6}\\\\a-1=0\ \ \ |+1\\a=1\\\\Answer:\ \boxed{a=-\dfrac{5}{6}\ \vee\ a=1}
VMariaS [17]3 years ago
6 0
(step 1) (6a+5)(a-1)=0

 (step 2) 6a+5=0 or a-1=0

answer is
a= -5/6 or a= 1
 i hope this helps! ;)
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2 years ago
Given g(x)=x^2 and h(x)= x-3 find (g ∘ h)(x)
DerKrebs [107]

Answer:

<h2>(g ∘ h)(x) = x² - 6x + 9</h2>

Step-by-step explanation:

g(x) = x²

h(x) = x - 3

To find (g ∘ h)(x) substitute h(x) into g(x) that's for every x in g(x) replace it with h(x)

That's

(g ∘ h)(x) = ( x - 3)²

= x² - 3x - 3x + 9

We have the final answer as

<h3>(g ∘ h)(x) = x² - 6x + 9</h3>

Hope this helps you

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