Line DE is 4 squares and Line BC is 8 squares.
The length of line DE is 1/2 of line BC
We have the given I = 10^-1 and I₀ = 10^-12.
Simply plugging in the values to the equation, we have:
L = 10log(10^-1/10^-12)
L = 110 Db
The answer is D.
(I used a scientific calculator in solving for L).
The slope is:
.
________________________________________________________Note:________________________________________________________slope = rise/ run = 15 ft/ 1000 ft ;
= 15/1000 = (15÷15) / (1000÷15) ;
= 1/ (200/3) = 1* (3/200) =
[tex] \frac{3}{200} [/tex] .
________________________________________________________
9514 1404 393
Answer:
-25 dollars per month
Step-by-step explanation:
It is convenient to compute the rate of change using points where the graph crosses grid intersections. A couple of these are ...
(months, dollars) = (1, 675) and (4, 600)
Using the slope formula, we have ...
m = (y2 -y1)/(x2 -x1)
m = (600 -675)/(4 -1) = -75/3 = -25 . . . . . dollars/month
Answer:
x and y
Step-by-step explanation:
Variables are always the numbers that're replaced with a letter. For example, in the equation:
2t+6
t would be the variable.
Hope this helps!! <3 :)