The potential energy of a 2-μc charge at that point in space is joules.
Given,
V=400v, q=2-μc=2*,
U(potential energy)=V*q=400*2*= joules.
<h3>Potential energy</h3>
The energy that an item retains due to its position in relation to other objects, internal tensions, electric charge, or other reasons is known as potential energy in physics. The gravitational potential energy of an object is based on its mass and the distance from the centre of mass of another object. Other common types of potential energy include the elastic potential energy of an extended spring and the electric potential energy of an electric charge in an electric field. The joule, denoted by the sign J, is the SI's definition of an energy unit.
The vectors that are described as gradients of a particular scalar function known as potential can be used to represent these forces, also known as conservative forces, at any location in space.
At a certain point in space there is a potential of 400 v. what is the potential energy of a 2-μc charge at that point in space? group of answer choices'
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Answer:
r² / 110² − 3z² / 1375² = 1
Explanation:
The equation of a hyperboloid (which is a hyperbola rotated about the z axis or conjugate axis) that is centered at the origin is:
x² / a² + y² / b² − z² / c² = 1
If the cross sections are circular rather than elliptical, then a = b.
(x² + y²) / a² − z² / c² = 1
Or, if you prefer cylindrical coordinates:
r² / a² − z² / c² = 1
We know that at z = 0, r = 110. And at z = -500, r = 130.
110² / a² − 0 = 1
130² / a² − (-500)² / c² = 1
Solving:
a² = 110²
c² = 1375² / 3
Plugging in:
r² / 110² − 3z² / 1375² = 1
The plus direction is going to go with the 10N to the right. Since the second force is applied in exactly the opposite direction, the net force 10 - 3 = 7 newtons to the right.
Acceleration due to gravity is a constant -9.8 m/s until terminal velocity (maximum freefall speed) is reached.
Answer ;
Minimum required volume = 0.635m3
Maximum internal pressure = 74.35bar
Explanation:
The detailed step by step calculation using the vanderwaal's equation of state for ideal gases is as shown in the attachment.