The acceleration due to gravity is 9.81m/s^2
Answer:
1.024 × 10⁸ m
Explanation:
The velocity v₀ of the orbit 8RE is v₀ = 8REω where ω = angular speed.
So, ω = v₀/8RE
For the orbit with radius R for it to maintain a circular orbit and velocity 2v₀, we have
2v₀ = Rω
substituting ω = v₀/8RE into the equation, we have
2v₀ = v₀R/8RE
dividing both sides by v₀, we have
2v₀/v₀ = R/8RE
2 = R/8RE
So, R = 2 × 8RE
R = 16RE
substituting RE = 6.4 × 10⁶ m
R = 16RE
= 16 × 6.4 × 10⁶ m
= 102.4 × 10⁶ m
= 1.024 × 10⁸ m
Answer:
1546.1 mph
Explanation:
Let's take the east direction as positive x-direction and north as positive y-direction.
The components of the initial velocity of the jet are:
while the components of the wind's velocity are
So, the components of the new velocity of the jet are:
And therefore, the new speed is the magnitude of the new velocity, so:
Answer:
11.7 s
Explanation:
In this problem, the rocket is moving in a uniform accelerated motion. We have the following data:
d = 223 m, the distance that the sled has to cover
, the acceleration of the rocket
We can use therefore the following SUVAT equation:
where
d is the distance
u = 0 is the initial velocity of the sled (it starts from rest)
t is the time
a is the acceleration
Re-arranging the equation and substituting the numbers, we find the time it takes for the rocket to cross the field:
Answer: a) 222k/m
b) 42.5W
c) if cold: 26.7C
If hot: 73.3C
Explanation:
If TH and TC are at the ends of the rod in the figure, then;
(A) 100 K / 45 cm = 2.22 K/cm or 222 K/m
(B) thermal conductivity constant for copper is 390 W/(m K).
Then the heat flow rate = Q/t
Q/t = [390 W/(m K)] (100 K) [ pi (0.0125 m)^2 ] / (0.45 m)
= 42.5 watts
(C) 12/45 = 4/15 = 0.2667
If the left end is the cold end, the answer will be 26.7 C
If the left end is the hot end, the answer will be 73.3 C