Answer:
514 cal
Explanation:
In order to calculate the lost heat by the amount of water you first take into account the following formula:
(1)
Q: heat lost by the amount of water = ?
m: mass of the water
c: specific heat of water = 1cal/g°C
T2: final temperature of water = 11°C
T1: initial temperature = 12°C
The amount of water is calculated by using the information about the density of water (1g/ml):
Then, you replace the values of all parameters in the equation (1):
The amount of water losses a heat of 514 cal
I'm not sure, but I'm pretty sure it depends.
Answer:
i = 0.00077A
Explanation:
Given:
loop radius, r = 3.0 cm = 0.03 m
Area, A = π x r² = π x 0.03² = 0.0028 m²
Magnetic Field, B = 0.75 T
Loop resistance, R = 18 Ω
time, t = 0.15 seconds
Now,
the induced emf is given as:
EMF = - BA/t .......1
Likewise,
EMF = iR.......2
Equate 1 and 2
iR = - BA/t
i = - BA/tR
i = 0.75×0.0028/0.15×18
i = 0.0021/2.7
i = 0.00077A
Answer:
θr = 55.2 °
Explanation:
The law of reflection states that the angle of incidence and the angles of reflection is the same.
Let's use trigonometry to find the angle between the reflected ray, where the horizontal distance x = 55.9 cm and the vertical distance is y = 38.9 cm
tan θ = y / x
tan θ = 38.9 / 55.9
θ = tan⁻¹ (0.6959)
θ = 34.8°
This angle is measured with respect to the x-axis (horizontal), but in general the angles in optics are measured from the y-axis so that the angle is
θ = 90 - 34.8
θr = 55.2 °
