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barxatty [35]
3 years ago
14

Given that mH = 1.007825 u, is the mass of a hydrogen atom 1H greater than, less than, or equal to 1/12 the mass of a 12C atom?

Select the correct answer and explanation. Given that = 1.007825 , is the mass of a hydrogen atom greater than, less than, or equal to 1/12 the mass of a atom? Select the correct answer and explanation. 1/12 of the mass of a 12C atom is greater than 1 u. Therefore, the mass of the hydrogen atom is greater than 1/12 of the mass of a 12C atom. 1/12 of the mass of a 12C atom is less than 1 u. Therefore, the mass of the hydrogen atom is less than 1/12 of the mass of a 12C atom. 1/12 of the mass of a 12C atom is exactly 1 u. Therefore, the mass of the hydrogen atom is less than 1/12 of the mass of a 12C atom. 1/12 of the mass of a 12C atom is exactly 1 u. Therefore, the mass of the hydrogen atom is greater than 1/12 of the mass of a 12C atom. 1/12 of the mass of a 12C atom is exactly 1 u. Therefore, the mass of the hydrogen atom is equal to 1/12 of the mass of a 12C atom.
Physics
1 answer:
Sholpan [36]3 years ago
3 0

Answer:

1/12 of the mass of a ¹²C atom is exactly 1u. Therefore, the mass of the hydrogen atom is greater than 1/12 of the mass of a ¹²C atom.

Explanation:

The unified atomic mass unit is defined as 1/12 of the mass of a ¹²C atom:

1u = 1/12 m ¹²C  

Also, the unified atomic mass unit is equal to the mass (in grams) of one mole of a substance, so knowing that 1 mol is equal to 6.022x10²³ atoms, the unified atomic mass unit measured in grams is:

1u = \frac{1g}{mol} \cdot \frac{1mol}{6.022 \cdot 10^{23} atoms} = 1.66 \cdot 10^{-24} g = 1.66 \cdot 10^{-27} kg      

Starting from this definition, we can calculate the mass of ¹H atom respect to the mass of a ¹²C atom:        

m ^{1}H = 1.007825u \cdot \frac{1/12 m ^{12}C}{1u} \cdot \frac{1.66\cdot 10^{-27}kg}{1/12 m ^{12}C} = 1.67 \cdot 10^{-27} kg      

Therefore, the mass of a ¹H atom is greater than 1/12 the mass of a ¹²C atom.

I hope it helps you!

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hram777 [196]

Gravitational force is determined by mass

Answer: Option B

<u>Explanation:</u>

According to Universal law of gravity, the gravitational force is directly proportional to the product of the masses of the objects and inversely proportional to the square of the distance between the objects.

            F=G \times \frac{m_{1} \times m_{2}}{r^{2}}

Where,

G – gravitational constant = \text { 6. } 67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}

\boldsymbol{m}_{1}, \boldsymbol{m}_{2} = masses of two objects

r – distance between the objects

So, as per this law, the gravitational force is found by mass.

8 0
3 years ago
Who speaks the line "Lord, what fools these mortals be"?
ivanzaharov [21]
The answer is D.Puck.

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3 0
3 years ago
A bicycle pump contains 20 cm3 of air at a pressure of 100 kPa. The air is then pumped in a tyre of volume 100 cm3. Calculate th
Natasha2012 [34]

Answer:

The pressure of the air in the tyre is 20 kPa

Explanation:

The parameters for the bicycle pump and tyre are;

The volume of air contained in the bicycle pump, V₁ = 20 cm³

The pressure of the air contained in the bicycle pump, P₁ = 100 kPa

The volume (available) of the tyre, where the air is pumped, V₂ = 100 cm³

Let P₂ represent the pressure in the tyre after the air is pumped

By Boyle's law, we have that at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure;

Mathematically, Boyle's law gives the following equation;

P₁ × V₁ = P₂ × V₂

∴ P₂ = (P₁ × V₁)/V₂

Substituting the known values gives;

P₂ = (100 kPa × 20 cm³)/(100 cm³)

∴ P₂ = 100 kPa × 1/5 = 20 kPa

P₂ = 20 kPa

The pressure of the air in the tyre = P₂ = 20 kPa.

7 0
3 years ago
A jet liner must reach a speed of 82 m/s for takeoff. If the
SIZIF [17.4K]

Answer:

The acceleration that the jet liner that must have is 2.241 meters per square second.

Explanation:

Let suppose that the jet liner accelerates uniformly. From statement we know the initial (v_{o}) and final speeds (v_{f}), measured in meters per second, of the aircraft and likewise the runway length (d), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed (a), measured in meters per square second:

a = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot d}

If we know that v_{o} = 0\,\frac{m}{s}, v_{f} = 82\,\frac{m}{s} and d = 1500\,m, then the acceleration that the jet must have is:

a = \frac{\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot (1500\,m)}

a = 2.241\,\frac{m}{s^{2}}

The acceleration that the jet liner that must have is 2.241 meters per square second.

3 0
2 years ago
Given that the atomic weight of hydrogen is approximately 1 gram per mole, use the method above to estimate the average molecula
denpristay [2]

Answer:

2

Explanation:

6 0
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