75kg man climbs a mountain 1000m high in 3hrs and uses 4100 joulse/min. (a) calculate the power consumption in watt, (b) what is his power output in useful work. (c) what is the efficiency of this man during the climb.
1 answer:
Answer:
Explanation:
a) Power consumption is 4100 J/min / 60 s/min = 68.3 W (atts)
work done raised the potential energy
b) 75(9.8)(1000) / (3(3600)) = 68.055555... 68.1 W
c) efficiency is 68.1 / 68.3 = 0.99593... or nearly 100%
Not a very likely scenario.
You might be interested in
Answer:
i don't know
Explanation:
sorry so much
Electromagnectic Waves Travel In A Vacuum
Most of the elements are metals
Answer:
A light beam incident on a diffraction grating consists of waves with two different wavelengths. The separation of the two first order lines is great if
the dispersion is great
