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noname [10]
3 years ago
11

A dump truck weighs 12000 pounds a garbage truck weighs 6.5 tons which car weighs more

Mathematics
2 answers:
LenKa [72]3 years ago
6 0
The garbage truck weighs more because one ton is 2000 pounds and 2000 times 6.5= 13000 hope this helped if not please reply I can teach it
strojnjashka [21]3 years ago
6 0
The garbage truck weighs more than the dump truck
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A rectangular hotel room is 11 feet wide and 25 feet long. What is its perimeter?
bekas [8.4K]

Answer:

The answer is 72

Step-by-step explanation:

The formula for perimeter is (L+W)x2

So in your case (11+25)x2

Or add all 4 sides of the rectangle up and you have your answer <3

5 0
2 years ago
Carlos needs 1.7 meters of wire for one project and 0.8 meters of wire for another project shade the model to represent the tota
vesna_86 [32]

Answer:

Step-by-step explanation:

Given that ;

Carlos needs 1.7 meters of wire for one project    &

0.8 meters of wire for another project

we are to shade the model to represent the total amount of wire Carlos needs .

NOW;

For both projects ; Carlos needs ( 1.7 + 0.8) meters of wire =  2.5 meters of wire

In  the  attached files below. the first picture shows the diagram attached to the question and the second one shows the shading of the model which represent the total amount of wire Carlos needs.

7 0
3 years ago
How many terms are in this expression?<br> 8+6k+10n
galina1969 [7]

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4 0
3 years ago
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The equation for a line passing through (-4, 6) and (1, 0) could be written in slope-intercept form as:
aleksandr82 [10.1K]

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7 0
3 years ago
1. In ABC, C is a right angle and BC = 11. If B = 30°, find AC. (1 point)
faltersainse [42]

Answer:

AC=\frac{11\sqrt{3}}{3}

Step-by-step explanation:

Given that triangle ABC is a right angle triangle. Where angle C is a right angle. Also we have been given that BC = 11, B = 30°. Now we need to find the value of AC.

Apply formula:

\tan\left(\theta\right)=\frac{opposite}{adjacent}

\tan\left(B\right)=\frac{AC}{BC}

\tan\left(30^o\right)=\frac{AC}{11}

\frac{1}{\sqrt{3}}=\frac{AC}{11}

\frac{11}{\sqrt{3}}=AC

AC=\frac{11}{\sqrt{3}}

or

AC=\frac{11}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}

or

AC=\frac{11\sqrt{3}}{3}

Hence final answer is AC=\frac{11\sqrt{3}}{3}.

7 0
3 years ago
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