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2 years ago

11

To prepare for a bake-off, Chuck used 0.53 kilogram of flour each day for 4 weeks. How many grams did Chuck use in those 4 weeks

?

2 answers:

andreyandreev [35.5K]2 years ago

8 0

0.53 * 4 =2.12 you multiply 0.53 * 4 I think

Zielflug [23.3K]2 years ago

5 0

Answer: 43.56

Step-by-step explanation:

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Un cuadro tiene 12 cm en sus lados ¿cuanto mide su area y su perimetro

uysha [10]

Answer:

area es 48 cm

el perimetro es 144cm

Step-by-step explanation:

5 0

2 years ago

A study of 420 comma 000 cell phone users found that 134 of them developed cancer of the brain or nervous system. Prior to this

Vesnalui [34]

Answer: (0.00306,0.00334)

Step-by-step explanation:

Given : Sample size : n= 420000

The number of users developed cancer of the brain or nervous system =134

Then , the proportion of users developed cancer of the brain or nervous system :

$p=\dfrac{134}{420000}\approx0.0032$

Significance level : $1-0.90=0.1$

Critical value : $z_{\alpha/2}=1.645$

The confidence interval for population proportion is given by :-

$p\ \pm\ z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.0032\pm (1.645)\sqrt{\dfrac{(0.0032)(1-0.0032)}{420000}}\approx0.0032\pm0.00014\\\\=(0.00306,0.00334)$

Hence, the 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system is (0.00306,0.00334).

4 0

2 years ago

A rectangle has an area of 6x ^ 2 + 7x - 3 square units. Which of the following could represent the perimeter of the rectangle i

Marina CMI [18]

I got a hold of me and her back on the number so i and she said she was ok

8 0

3 years ago

The focal lengths of the objective lens and the eyepiece of a microscope are 0.50 cm and 2.0 cm, respectively, and their separat

VladimirAG [237]

Answer:

- 103.7

Step-by-step explanation:

Given:

Focal length of the eyepiece, f = 2.0 cm

Focal length of the objective lens, f' = 0.50 cm

Separation for minimum eyestrain = 6,0 cm

Image distance, v = - 25 cm

Now, from the lens formula,

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

here, u is the object distance

on substituting the respective values, we get

$\frac{1}{2}=\frac{1}{u}+\frac{1}{-25}$

or

u = 1.852 cm

also, the separation is adjusted for minimum eyestrain,

therefore, image distance for the objective lens, v' = 6 - 1.852 = 4.148 cm

Now, for the objective lens

using the lens formula, we get

$\frac{1}{0.5}=\frac{1}{u'}+\frac{1}{4.418}$

Here, u' is the distance between the physical object and objective lens

or

u' = 0.568 cm

Thus,

Magnification, m = $-\frac{vv'}{ff'}$

or

m = $-\frac{25\times4.418}{0.5\times2}$

or

m = - 103.7

4 0

2 years ago

I dont understand please help

DiKsa [7]

$2 \frac{1}{2}+(-2\frac{1}{4})$

This is equal to:

$2\frac{1}{2}-2\frac{1}{4}$

When you add a negative number, it turns into subtraction.

First, I would change it to mixed numbers:

$\frac{5}{2}-\frac{9}{4}$

Now, you need to change the denominators to make sure they are the same on both fractions. I changed the first fraction's denominator to 4 so they match. You can do this by multiplying the numerator by 2:

$\frac{10}{4}-\frac{9}{4}$

Now, you simply subtract:

10-9=1

1/4 is your answer.

I hope this helps :)

3 0

2 years ago