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3 years ago

11

To prepare for a bake-off, Chuck used 0.53 kilogram of flour each day for 4 weeks. How many grams did Chuck use in those 4 weeks

?

2 answers:

andreyandreev [35.5K]3 years ago

8 0

0.53 * 4 =2.12 you multiply 0.53 * 4 I think

Zielflug [23.3K]3 years ago

5 0

Answer: 43.56

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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3x - 4y = 13

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3x - 4y = 13

8x + 4y = 20

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3 years ago

What is 5+5= and 5×2

saveliy_v [14]

Answer:

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Step-by-step explanation:

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Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random

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Answer:

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

Step-by-step explanation:

Given

$n = 200$

$x_1 = 34$ -- City C

$x_2 = 54$ --- City K

Required

Determine the 90% confidence interval

This is calculated using:

$CI = \bar x \± z\frac{\sigma}{\sqrt n}$

Calculating $\bar x$

$\bar x = \bar x_1 - \bar x_2$

$\bar x = \frac{x_1}{n} - \frac{x_2}{n}$

$\bar x = \frac{34}{200} - \frac{54}{200}$

$\bar x = 0.17 - 0.27$

For a 90% confidence level, the z-score is 1.65. So:

$z = 1.65$

Calculating the standard deviation $\sigma$

$\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }$

So:

$\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }$

$\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}$

So:

$CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}$

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3 years ago