Answer:
You determine the net force of an object by adding up all of the individual forces.
Explanation:
If N is the number of forces acting on the body, the net force formula is:
= + + ....+
Where , , and as forces acting on a body.
When a body is at rest, the net force formula is given by
Fa = Applied force and
Fg = Gravitational force.
<u>Example:</u>
A truck is standing still and a force of 70 N is applied on it. If the frictional force is 20 N, then what will be the net force?
Solution:
Given
Applied force Fa = 70 N
Frictional force Ff = 20 N
The net force formula is given by
FNet = Fa + Ff
FNet = 70 + (-20)
FNet = 50 N
Therefore, the net force is 50 N
A=dv/ dt
a=(v2-v1)/(t2-t1)
a=(60-50)/(10-0)
a=10/10
a=1
it's acceleration is 1 km/s^(2) or 1000 m/s^(2)
Hope I can help u
Chemical change
Explanation:
Often times, in chemical reactions, a temperature change indicates that a chemical change has occurred.
What is a chemical change?
- It is a kind of change in which new products are formed.
- Chemical changes are usually accompanied by energy changes in reactions.
- The process is not easily reversible.
- It usually involve a change in mass.
- Requires considerable amount of energy
When temperature change occurs, it usually denotes chemical change.
learn more:
Chemical change brainly.com/question/9388643
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Answer:
Condensation and Depositon
Explanation:
Condensation is from gas to liquid
Deposition is from gas to solid
Answer:
Its pressure will be 0.54 atm at 100 K.
Explanation:
Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.
Gay-Lussac's law can be expressed mathematically as the quotient between pressure and temperature equal to a constant:
Studying two different states, an initial state 1 and a final state 2, it is satisfied:
In this case:
- P1= 1.75 atm
- T1= 50 °C= 323 K (being 0 C=273 K)
- P2= ?
- T2= 100 K
Replacing:
Solving:
P2= 0.54 atm
<u><em>Its pressure will be 0.54 atm at 100 K.</em></u>