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AnnyKZ [126]
4 years ago
12

HELP! THIS IS SCIENCE

Chemistry
2 answers:
Alexxx [7]4 years ago
7 0
This is known as Rutherford's gold foil experiment. To align with J.J Thompson's Plum Pudding Model, he expects a beam of alpha particles to just pass through the gold foil undisturbed. However, some were deflected at certain angles. Alpha particles are positive, so it would just go straight through the nucleus, but will deflect if it hits the electrons. <em>Therefore, the answer is: </em><span><em>Particles that struck the nucleus went straight.</em></span>
juin [17]4 years ago
3 0

Answer is: Electron cloud allowed the particles to pass through.

Rutherford theorized that atoms have their charge concentrated in a very small nucleus.

This was famous Rutherford's Gold Foil Experiment: he bombarded thin foil of gold with positive alpha particles (helium atom particles, consist of two protons and two neutrons).  

Rutherford observed the deflection of alpha particles on the photographic film and notice that most of alpha particles passed straight through foil.

That is different from Plum Pudding model, because it shows that most of the atom is empty space.

According to Rutherford model of the atom:  

1) Atoms have their charge concentrated in a very small nucleus.  

2) Major space in an atom is empty.  

3) Atoms nucleus is surrounded by negatively charged particles called electrons.  

4) An atom is electrically neutral.

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Explanation:

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3 0
3 years ago
PLEASE HELP ME I BEG YOU
VladimirAG [237]

The average kinetic energy of 1 mole of a gas at -32 degrees Celsius is:
 
3.80 x 103 J

The relationship between volume and temperature of a gas, when pressure and moles of a gas are held constant, is: V*T = k.

FALSE

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TRUE

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35 - AB

36 -  BD

33 - true

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4 0
3 years ago
How many photons are produced in a laser pulse of 0.497 J at 469 nm?
dimulka [17.4K]
<span>E=hν</span> where E is the energy of a single photon, and ν is the frequency of a single photon. We recall that a photon traveling at the speed of light c and a frequency ν will have a wavelength λ given by <span>λ=<span>cν</span></span>λ will have an energy given by <span>E=<span><span>hc</span>λ</span></span><span>λ=657</span> nm. This will be <span>E=<span><span>(6.626×<span>10<span>−34</span></span>)(2.998×<span>108</span>)</span><span>(657×<span>10<span>−9</span></span>)</span></span>=3.0235×<span>10<span>−19</span></span>J</span> So we now know the energy of one photon of wavelength 657 nm. To find out how many photons are in a laser pulse of 0.363 Joules, we simply divide the pulse energy by the photon energy or <span>N=<span><span>E<span>pulse </span></span><span>E<span>photon</span></span></span>=<span>0.363<span>3.0235×<span>10<span>−19</span></span></span></span>=1.2×<span>1018</span></span>So there would be <span>1.2×<span>1018</span></span><span> photons of wavelength 657 nm in a pulse of laser light of energy 0.363 Joules.</span>
7 0
3 years ago
Read 2 more answers
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