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3 years ago

HELP! THIS IS SCIENCE

2 answers:

7 0

This is known as Rutherford's gold foil experiment. To align with J.J Thompson's Plum Pudding Model, he expects a beam of alpha particles to just pass through the gold foil undisturbed. However, some were deflected at certain angles. Alpha particles are positive, so it would just go straight through the nucleus, but will deflect if it hits the electrons. Therefore, the answer is: Particles that struck the nucleus went straight.

juin [17]3 years ago

3 0

Answer is: Electron cloud allowed the particles to pass through.

Rutherford theorized that atoms have their charge concentrated in a very small nucleus.

This was famous Rutherford's Gold Foil Experiment: he bombarded thin foil of gold with positive alpha particles (helium atom particles, consist of two protons and two neutrons).

Rutherford observed the deflection of alpha particles on the photographic film and notice that most of alpha particles passed straight through foil.

That is different from Plum Pudding model, because it shows that most of the atom is empty space.

According to Rutherford model of the atom:

1) Atoms have their charge concentrated in a very small nucleus.

2) Major space in an atom is empty.

3) Atoms nucleus is surrounded by negatively charged particles called electrons.

4) An atom is electrically neutral.

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Why do we use the mole concept ??

Kaylis [27]

Answer:

Here

Explanation:

Chemists need the mole concept to bridge the gap between the microscopic world of atoms to the macroscopic world of humans. As you know, the molecular level consists of particles that are invisible to us.

7 0

3 years ago

Read 2 more answers

When the volume of a gas is

Montano1993 [528]

Answer:

$\boxed {\boxed {\sf 232.9 \textdegree C}}$

Explanation:

This question asks us to find the temperature change given a volume change. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula is:

$\frac {V_1}{T_1}= \frac{V_2}{T_2}$

The volume of the gas starts at 250 milliliters and the temperature is 137 °C.

$\frac{250 \ mL}{137 \textdegree C}= \frac{V_2}{T_2}$

The volume of the gas is increased to 425 milliliters, but the temperature is unknown.

$\frac{250 \ mL}{137 \textdegree C}= \frac{425 \ mL}{T_2}$

We are solving for the new temperature, so we must isolate the variable T₂. First, cross multiply. Multiply the first numerator and second denominator, then multiply the first denominator and second numerator.

$250 \ mL * T_2 = 137 \textdegree C * 425 \ mL$

Now the variable is being multiplied by 250 milliliters. The inverse of multiplication is division. Divide both sides of the equation by 250 mL.

$\frac{250 \ mL * T_2}{250 \ mL}=\frac{ 137 \textdegree C * 425 \ mL}{250 \ mL}$

$T_2=\frac{ 137 \textdegree C * 425 \ mL}{250 \ mL}$

The units of milliliters (mL) cancel.

$T_2=\frac{ 137 \textdegree C * 425 }{250 }$

$T_2= \frac{58225}{250} \textdegree C$

$T_2=232.9 \textdegree C$

The temperature changes to 232.9 degrees Celsius.

3 0

3 years ago

9. Based on your work with benzoic acid, show the reaction between salicylic acid and potassium hydroxide. Label the acid, base,

shepuryov [24]

Answer:

Explanation:

Salicylic Acid:

Salicylic Acid is an hydroxy acid that is found as a natural compound in plants. It's IUPAC name is 2-hydroxybenzoic acid. Salicylic acid has an odorless white to light tan solid color. It sinks and mixes very slow with water.

Acid: An acid is a substance that produce hydrogen ion or proton when dissolved in water

Base: A base is a substance that will neutralize an acid to yield salt and water

Conjugate Base: This is a substance formed when an acid loses an hydrogen ion or proton when it dissolved in water.

Conjugate Acid: This is a substance formed when a base accept a proton from from any acid, when it dissolved in water.

Reaction between salicylic acid and potassium hydroxide

HOC₆H₄COOH(aq) + KOH(aq) ⇄ HOC₆H₄COOK(aq) + H₂O(l)

Acid ⇒ HOC₆H₄COOH (salicylic acid)

Base ⇒ KOH (potassium hydroxide)

Conjugate acid ⇒ H₂O (water)

conjugate base ⇒ HOC₆H₄COOK ( 2-hydroxypotasium benzoate)

3 0

3 years ago

If I have 7.5 L of a gas in a piston at a pressure of 1.75 atm and compress the gas until its volume is 3.7 L, what will the new

Sergio [31]

Answer:

3.55atm

Explanation:

We will apply Boyle's law formula in solving this problem.

P1V1 = P2V2

And with values given in the question

P1=initial pressure of gas = 1.75atm

V1=initial volume of gas =7.5L

P2=final pressure of gas inside new piston in atm

V2=final volume of gas = 3.7L

We need to find the final pressure

From the equation, P1V1 = P2V2,

We make P2 subject

P2 = (P1V1) / V2

P2 = (1.75×7.5)/3.7

P2=3.55atm

Therefore, the new pressure inside the piston is 3.55atm

7 0

3 years ago

Which term names a metamorphic change in rocks over a wide area from tectonic forces in Earth's crust and mantle? A. local metam

Pavlova-9 [17]

D is the answer. A, B,C are absurd. Doing a little word right there.

8 0

3 years ago

Read 2 more answers