Which two solutions, when mixed together, will undergo a double replacement reaction and form a white, solid substance?

1 answer:

4 0

$AgNO_3 + KCl$ → $AgCl + KNO_3$ undergo a double replacement reaction and form a white, solid substance. Hence, option B is correct.

<h3>What is a double replacement reaction?</h3>

A double replacement reaction is a type of chemical reaction that occurs when two reactants exchange cations or anions to yield two new products.

Double-replacement reactions generally occur between substances in aqueous solution. In order for a reaction to occur, one of the products is usually a solid precipitate, a gas, or a molecular compound such as water.

$AgNO_3 + KCl$ → $AgCl + KNO_3$ undergo a double replacement reaction and form a white, solid substance.

Hence, option B is correct.

Learn more about the double replacement reaction here:

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When H2SO4 is added to PbI2, a precipitate of PbSO4 forms. The PbSO4 is then filtered from the solution, dried, and weighed. If

Nookie1986 [14]

Answer:

$n_{I^-}=3.11x10^{-4}molI^-$

Explanation:

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In this case, the undergoing chemical reaction is shown below:

$H_2SO_4(aq)+PbI_2(aq)\rightarrow PbSO_4(s)+2HI(aq)$

Thus, we obtain 0.0471 g of lead (II) sulfate, the iodide ions in the original solution are computed below by stoichiometry, taking into account that into 1 mole of lead (II) iodide there are 2 moles of iodide ions:

$n_{I^-}=0.0471gPbSO_4*\frac{1molPbSO_4}{303.26gPbSO_4}*\frac{1molPbI_2}{1molPbSO_4}*\frac{2molI^-}{1molPbI_2} \\n_{I^-}=3.11x10^{-4}molI^-$