Answer:
Coefficient of ![C_3H_8O_2=3](https://tex.z-dn.net/?f=C_3H_8O_2%3D3)
Coefficient of
=8
Explanation:
We are given that a reaction in which
reacts with ![KMnO_4](https://tex.z-dn.net/?f=KMnO_4)
We have to find the coefficient of each reactants in balanced reaction
![3C_3H_8O_2(aq)+8KMnO_4(aq)\rightarrow 3C_3H_2O_4K_2(aq)+8MnO_2(aq)+2KOH+8H_2O](https://tex.z-dn.net/?f=3C_3H_8O_2%28aq%29%2B8KMnO_4%28aq%29%5Crightarrow%203C_3H_2O_4K_2%28aq%29%2B8MnO_2%28aq%29%2B2KOH%2B8H_2O)
Coefficient is defined the constant value multiplied with a reactant in a reaction.
Coefficient of
=3
Coefficient of ![KMnO_4=8](https://tex.z-dn.net/?f=KMnO_4%3D8)
Coefficient of ![C_3H_2O_4K_2=3](https://tex.z-dn.net/?f=C_3H_2O_4K_2%3D3)
Coefficient of ![MnO_2=8](https://tex.z-dn.net/?f=MnO_2%3D8)
Coefficient of ![H_2O=8](https://tex.z-dn.net/?f=H_2O%3D8)
Coefficient of KOH=2
Hence, Coefficient of
and coefficient of ![KMnO_4=8](https://tex.z-dn.net/?f=KMnO_4%3D8)
Maybe this can help.
In mechanics, speed increase is the pace of progress of the speed of an article regarding time (acceleration). Speed increases are vector amounts (in that they have greatness and direction). The direction of an item's speed increase is given by the direction of the net power following up on that article. The size of an item's speed increase, as depicted by Newton's Second Law, is the consolidated impact of two causes:
the net equilibrium of all outer powers acting onto that item — size is straightforwardly relative to this net coming about force;
that article's mass, contingent upon the materials out of which it is made — extent is conversely relative to the item's mass.
Answer:
31.1°C
Explanation:
Given parameters:
Temperature = 88°F
The formula of the to convert is:
T°F = T°C - 32 / 1.8 = ![\frac{TC - 32}{1.8}](https://tex.z-dn.net/?f=%5Cfrac%7BTC%20-%2032%7D%7B1.8%7D)
Now input the parameters and solve;
T°F =![\frac{ 88 -32}{1.8}](https://tex.z-dn.net/?f=%5Cfrac%7B%2088%20%20-32%7D%7B1.8%7D)
T°F = 31.1°C
Answer:
Molar concentration of CO₂ in equilibrium is 0.17996M
Explanation:
Based on the reaction:
NiO(s) + CO(g) ⇆ Ni(s) + CO₂(g)
kc is defined as:
kc = [CO₂] / [CO] = 4.0x10³ <em>(1)</em>
As initial concentration of CO is 0.18M, the concentrations in equilibrium are:
[CO] = 0.18000M - x
[CO₂] = x
Replacing in (1):
4.0x10³ = x / (0.18000-x)
720 - 4000x = x
720 = 4001x
x = 0.17996
Thus, concentrations in equilibrium are:
[CO] = 0.18000M - 0.17996 = 4.0x10⁻⁵
[CO₂] = x = <em>0.17996M</em>
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Thus, <em>molar concentration of CO₂ in equilibrium is 0.17996M</em>
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I hope it helps!