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3 years ago

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In order for a chemical reaction to take place, a certain amount of _____________ must be present. A. heat B. friction C. chemic

als D. energy
I NEED THE ANSWER LIKE..RIGHT NOW!!!!!!!!

2 answers:

ch4aika [34]3 years ago

6 0

I believe it'd be energy.

Anna35 [415]3 years ago

3 0

The right answer is energy

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An object of mass 10.0 kg is initially at rest. A 100 N force causes it to move horizontally through a distance of 6.00 m. What

TEA [102]

Answer:

The answer to the question is

The change in the kinetic energy of the object is 600 J

Explanation:

The known variables are,

Mass of object, m = 100 kg

Force of object, F = 100 N

The relation for kinetic energy = KE = $\frac{1}{2} * m * v^{2}$ = 0.5·m·v²

Therefore to find v we first find the acceleration from

F = m·a =10.0 kg × a = 100 N,

Where a = acceleration of the object =100/10 = 10 m/s²

To find the velocity, v, we use the relationship

v² = u² + 2 × a × S, where S is the distance of motion = 6.00 m and u is the initial velocity, u = 0 m/s, therefore

v² = 0 + 2 × 10 m/s² × 6 m = 120 m²/s² or v = 10.95 m/s

Therefore KE = 0.5 × 10 kg × (10.95 m/s)² = 600 J

where the initial velocity, u = 0 m/s

Initial kinetic energy of the object = KE₁ = 0.5 × 10 × 0² = 0

The change in kinetic energy of the object = 600 J - 0 J = 600 J

5 0

4 years ago

How many atoms are in c6h4c12

Mekhanik [1.2K]

Answer:

their are a it is in the chemicle

Explanation:18 carbon and 4 hydrogen

so it is a toatle of 22 atoms

6 0

3 years ago

For the reaction A + B + C → D + E, the initial reaction rate was measured for various initial concentrations of reactants. The

Alik [6]

Answer : The rate for trial 5 will be $4.25\times 10^{-2}Ms^{-1}$

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$A+B+C\rightarrow D+E$

Rate law expression for the reaction:

$\text{Rate}=k[A]^a[B]^b[C]^c$

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

$6.0\times 10^{-4}=k(0.20)^a(0.20)^b(0.20)^c$ ....(1)

Expression for rate law for second observation:

$1.8\times 10^{-3}=k(0.20)^a(0.20)^b(0.60)^c$ ....(2)

Expression for rate law for third observation:

$2.4\times 10^{-3}=k(0.40)^a(0.20)^b(0.20)^c$ ....(3)

Expression for rate law for fourth observation:

$2.4\times 10^{-3}=k(0.40)^a(0.40)^b(0.20)^c$ ....(4)

Dividing 1 from 2, we get:

$\frac{1.8\times 10^{-3}}{6.0\times 10^{-4}}=\frac{k(0.20)^a(0.20)^b(0.60)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\3=3^c\\c=1$

Dividing 1 from 3, we get:

$\frac{2.4\times 10^{-3}}{6.0\times 10^{-4}}=\frac{k(0.40)^a(0.20)^b(0.20)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\4=2^a\\a=2$

Dividing 3 from 4, we get:

$\frac{2.4\times 10^{-3}}{2.4\times 10^{-3}}=\frac{k(0.40)^a(0.40)^b(0.20)^c}{k(0.40)^a(0.20)^b(0.20)^c}\\\\1=2^b\\b=0$

Thus, the rate law becomes:

$\text{Rate}=k[A]^2[B]^0[C]^1$

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

$6.0\times 10^{-4}=k(0.20)^2(0.20)^0(0.20)^1$

$k=7.5\times 10^{-2}M^{-2}s^{-1}$

Thus, the value of the rate constant 'k' for this reaction is $7.5\times 10^{-2}M^{-2}s^{-1}$

Now we have to calculate the rate for trial 5 that starts with 0.90 M of reagent A, 0.60 M of reagents B and 0.70 M of reagent C.

$\text{Rate}=k[A]^2[B]^0[C]^1$

$\text{Rate}=(7.5\times 10^{-2})\times (0.90)^2(0.60)^0(0.70)^1$

$\text{Rate}=4.25\times 10^{-2}Ms^{-1}$

Therefore, the rate for trial 5 will be $4.25\times 10^{-2}Ms^{-1}$

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3 years ago

What are 3 characteristics of a mixture?

bogdanovich [222]

Answer:

The substances in a mixture can be separated using physical methods such as filtration, freezing, and distillation.

There is little, see Enthalpy of mixing, or no energy change when a mixture forms.

Mixtures have variable compositions, while compounds have a fixed, definite formula.

Explanation:

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4 years ago

How is sedimentary rocks formed?<br>

mel-nik [20]

Answer:

Sedimentary rocks are formed when sediment is deposited out of air, ice, wind, gravity, or water flows carrying the particles in suspension

Explanation:

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3 years ago