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Slav-nsk [51]
3 years ago
12

What if cell differentiation did not occur?

Chemistry
1 answer:
Galina-37 [17]3 years ago
4 0

Answer:

when cells begin dividing it goes through mitosis then nucleus divides following to cytoplasm if cell isn't controlled it may cuase disease or cancer

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The limiting reactants appeared to be _______<br><br> Because___________
Igoryamba

Answer:

The limiting reagents seemed to be those that were consumed first .

Because when this reagent is consumed, the reaction stops. The quantity of this determines the total quantity of the product formed.

Explanation:

A limiting reagent is one that is consumed in its entirety. In this way, it delimits the amount of product that can be formed.

Take the case of two substances that interact and produce a chemical reaction. If one of the substances runs out as it is consumed during the process, the reaction will stop. The reagent consumed acts as a limiting reagent, that is, it limits the possibility of the reaction proceeding, and therefore it also limits the amount of the product generated by the reaction.

8 0
3 years ago
For a beryllium-gold voltaic cell containing Be2+(aq) and Au3+(aq) solutions, do the following. (a) Identify the cathode. (Inclu
OLEGan [10]

Answer:  Gold act as cathode.

Explanation:

Standard potential for an electrochemical cell is given by:

E^0{cell} = standard electrode potential =E^0{cathode}-E^0{anode}

The E^0 values have to be reduction potentials.  

Reduction potentials for given elements

E^o_{Be^{2+}/Be}=-1.97V

E^o_{Au^{3+}/Au}=+1.40V

The element Be with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element Au with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.

Cathode : 2Au^{3+}+6e^-\rightarrow 2Au

Anode : 3Be\rightarrow 3Be^{2+}+6e^-

3Be+2Au^{3+}(aq)\rightarrow 2Au+3Be^{2+}(aq)

Thus gold act as cathode.

7 0
3 years ago
Analyze the reaction to determine whether the
Bumek [7]

Answer: Exothermic

Explanation: Looking at the graph, you see that the reaction started with more energy than it ended with, meaning it gave out its energy over the course of the reaction. This is also confirmed by the reaction equation, which shows the energy (891 kJ) on the right side of the equation.

6 0
3 years ago
Read 2 more answers
¿Cómo se llama el grupo IIA de la tabla periódica?
Verdich [7]

Answer:

los metales alcalinotérreos: berilio (Be), magnesio (Mg), calcio (Ca), estroncio (Sr), bario (Ba) y radio (Ra).

o simplemente llamado grupo 2A

Explanation:

8 0
2 years ago
What is list of solutions
VashaNatasha [74]
Depends on what the problems are, you are going to have to be a bit more specific, Young Padawan
3 0
3 years ago
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