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Slav-nsk [51]
4 years ago
12

What if cell differentiation did not occur?

Chemistry
1 answer:
Galina-37 [17]4 years ago
4 0

Answer:

when cells begin dividing it goes through mitosis then nucleus divides following to cytoplasm if cell isn't controlled it may cuase disease or cancer

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A 2. 00 g sample of cocl2. x h2o is dried in an oven. when the anhydrous salt is removed from the oven, its mass is 1. 565 g. wh
timofeeve [1]

It is Cobalt(II)chloride dihydrate. The value of x is 2.

First, we have to determine the mass of H₂O that was evaporated upon heating which will be = 2.00g - 1.56 g

                                 = 0.435 g

So,

CoCl₂ + x.H₂O → CoCl₂.xH₂O

Molecular mass of CoCl₂ = 129.839 g/mol

Molecular mass of H₂O = 18 g/mol

Weight of sample after heating = 1.565 g

Weight of H₂O evaporated = 0.435 g

Hence,

           18x = \frac{129.839X0.435}{1.565} \\x = \frac{55.48}{28.17} \\x = 1.9

           x ≈ 2

So, it is Cobalt(II)chloride dihydrate.

Learn more about molecular mass here:

brainly.com/question/13147431

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3 0
2 years ago
The reaction: 2 SO2(g) + O2(g) --> 2 SO3(g) has an equilibrium constant of K1. What is the K value for the reaction: SO3(g) -
Murljashka [212]

<u>Answer:</u> The value of equilibrium constant for reverse reaction is (\frac{1}{K_1})^{1/2}

<u>Explanation:</u>

The given chemical equation follows:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

The equilibrium constant for the above equation is K_1

We need to calculate the equilibrium constant for the reverse equation of above chemical equation, which is:

SO_3(g)\rightarrow SO_2(g)+\frac{1}{2}O_2(g)

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

If the equation is multiplied by a factor of '\frac{1}{2}', the equilibrium constant of the reverse reaction will be the 1/2 power of the equilibrium constant  of initial reaction.

The value of equilibrium constant for reverse reaction is:

K_{eq}'=(\frac{1}{K_1})^{1/2}

Hence, the value of equilibrium constant for reverse reaction is (\frac{1}{K_1})^{1/2}

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