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Vedmedyk [2.9K]
3 years ago
7

Can u help me find the value of "y": 3y= 6x+3x+36

Mathematics
1 answer:
jolli1 [7]3 years ago
7 0
3y=6x+3x+36\\\\3y=9x+36\ \ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\y=\frac{9x}{3}+\frac{36}{3}\\\\\boxed{y=3x+12}
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Answer:

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Step-by-step explanation:

There is no solution for system of equations:  a_1x+b_1y=c_1\\a_2y+b_2y=c_2

if:     a_1=a_2\quad and\quad b_1=b_2\quad and\quad \bold{c_1\ne c_2}

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kx-3y=4\\ 4x-5y=7\\\\ (kx-3y)\cdot5=4\cdot5\\ (4x-5y)\cdot3=7\cdot3\\\\ 5kx-15y=20\\ 12x-15y=21

Now we have  b₁=b₂ and c₁≠c₂ so the system has no solution if a₁=a₂

5k = 12

÷5     ÷5

k = ¹²/₅

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