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Vedmedyk [2.9K]
3 years ago
7

Can u help me find the value of "y": 3y= 6x+3x+36

Mathematics
1 answer:
jolli1 [7]3 years ago
7 0
3y=6x+3x+36\\\\3y=9x+36\ \ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\y=\frac{9x}{3}+\frac{36}{3}\\\\\boxed{y=3x+12}
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How can you tell if radicals are like radicals
valentina_108 [34]
Like radicals are radicals that have the same root number AND radicand (expression under the root).
And there ya have it!

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~Brooke❤️
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3 years ago
Read 2 more answers
Solution to (x-2) (x+10) = 13
Grace [21]

Answer:

-11,3

Step-by-step explanation: using foil (x-2)(X+10)=x^2+8x-20

x^2+8x-20-13=13-13 X^2+8x-33=0 factoring you get (x+11)(x-3)=0 so x+11=0

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if you found this helpful please thank me

4 0
3 years ago
A cone shaped popcorn cup has a radius of 5 cm and a height of 9cm. How many cubic cm of popcorn can the cup hold? Use 3.14 as a
katovenus [111]

Answer:

The cup can hold <u>235.5 cubic cm</u> of popcorn.

Step-by-step explanation:

Given:

A cone shaped popcorn cup has a radius of 5 cm and a height of 9cm.

Use 3.14 as an approximation for pi.

Now, to find cubic cm of popcorn the cup can hold.

Radius ( r ) = 5 cm.

Height ( h ) = 9 cm.

π = 3.14 ( as per question ).

So, to get the cubic cm of popcorn the cup can hold we put formula of volume:

Volume = \pi r^2\frac{h}{3}

Volume=3.14\times 5^2\times \frac{9}{3}

Volume=3.14\times 25\times 3

Volume=235.5\ cubic\ cm.

Therefore, the cup can hold 235.5 cubic cm of popcorn.

3 0
4 years ago
A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa
diamong [38]

Answer:

p_v= 0.01

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b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

Solution to the problem

The hypothesis for this case are:

Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}= \mu_D

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C,D

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have p=4 groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

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SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

p_v= 0.01

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b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

8 0
4 years ago
Evaluate each function over the set of real numbers.
zalisa [80]

Answer:

0

Step-by-step explanation:

3 0
3 years ago
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