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3 years ago

Evaluate each function over the set of real numbers.

Mathematics

1 answer:

zalisa [80]3 years ago

3 0

Answer:

Step-by-step explanation:

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Please help with geometry problems

sertanlavr [38]

Answer:

put your best gees

Step-by-step explanation:

6 0

2 years ago

If f(x) = 1/6 x-8, then f^-1(x)=

bezimeni [28]

Answer:

f^-1(x) is 6x + 48

f(x) = 1/6x - 8

To find f^-1(x) equate f(x) to y

That's

f(x) = y

y = 1/6x - 8

Next interchange the terms

We have

x = 1/6y - 8

Make y the subject

Multiply through by 6

We have

6x = y - 48

y = 6x + 48

Therefore f^-1(x) is 6x + 48

Hope this helps you

5 0

3 years ago

Which point on the number line represents an integer? Justify your response.

Romashka-Z-Leto [24]

Answer:

All of them are integers

Step-by-step explanation:

All are numbers of integers so all should be correct

8 0

3 years ago

Read 2 more answers

Express -23 in the form bi where b is a real number TIME SENSITIVE

balu736 [363]

Answer:

Step-by-step explanation:

i stands for square root of negative 1. If you multiple i and square root of 23 you will end up with the original

4 0

3 years ago

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

3 years ago