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Damm [24]
3 years ago
6

In an experiment in space, one proton is held fixed and another proton is released from rest a distance of 1.00 mm away. part a

what is the initial acceleration of the proton after it is released
Physics
1 answer:
mihalych1998 [28]3 years ago
8 0
<span>We can use Coulomb's law to find the force F acting on the proton that is released. F = k x Q1 x Q2 / r^2 k = 9 x 10^9 Q1 is the charge on one proton which is 1.6 x 10^{-19} C Q2 is the same charge on the other proton r is the distance between the protons F = (9x10^9) x (1.6 x 10^{-19} C) x (1.6 x 10^{-19} C) / (10^{-3})^2 F = 2.304 x 10^{-22} N We can use the force to find the acceleration. F = ma a = F / m a = (2.304 x 10^{-22} N) / (1.67 x 10^{-27} kg) a = 1.38 x 10^5 m/s^2 The initial acceleration of the proton is 1.38 x 10^5 m/s^2</span>
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An object is held at an unknown height above Earth’s surface, where the acceleration due to gravity of the object is considered
Aleks04 [339]

Answer:

Options A and B.

Explanation:

Gravitational acceleration, initial height, intial speed and time are required to determine final speed. The option D is incorrect, since speed varies in time. Option C is dimentionally wrong.

The correct strategy is calculating the initial height from option B. Later, substituting time in equation A to derive an expression of the final velocity in terms of position. Hence, the required equations are options A and B.

7 0
3 years ago
A spaceship travels at approximately 0. 25c with respect to earth. this means 24 hours at the spaceship will be x hours to us on
Blababa [14]

The time passed on earth is  mathematically given as

t' = 24.79 hrs

<h3>What is the time passed on earth?</h3>

Generally, the equation for is time  mathematically given as

t' = \gamma t

Where

\gamma = Lorentz\ factor \\\\\gamma = 1/ \sqrt {(1 - v^2/c^2)}

t' = t/ \sqrt {(1 - v^2/c^2)}

Therefore

t' = 24/ \sqrt {(1 - (0.25c/c)^2) }

t'= 24/ \sqrt {(1 - 0.25^2)

t' = 24.79 hrs

In conclusion, the time passed on earth

t' = 24.79 hrs

Read more about the time

brainly.com/question/28050940

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4 0
1 year ago
Unit of gravitational force ​
azamat

Answer:

Newton

Explanation:

9.80665 × kgf = 1 Newton N

1 kilogram force (kgf) was the force of gravity, which is pushing a mass of 1 kg at one place in the world on the ground; calculated according to Newton's law force = mass × acceleration.

3 0
3 years ago
If you add together all of forces exerted on an object and get a non zero value this is called the _____ force on the object
butalik [34]

Your answer would be the;  <u>NET</u>  force on the object.   Refer to Newton's Laws of Forces and Motion.







Hope that helps!!!!!!!!!!!!!!!!                                        : )

8 0
3 years ago
Read 2 more answers
Pls help meeee!!! will mark brainliest!!​
Vitek1552 [10]

Answer:

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hope it helps

5 0
2 years ago
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