In an experiment in space, one proton is held fixed and another proton is released from rest a distance of 1.00 mm away. part a
1 answer:
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Answer:
(a) 1.58 V
(b) 0.0126 Wb
(c) 0.0493 V
Solution:
As per the question:
No. of turns in the coil, N = 400 turns
Self Inductance of the coil, L = 7.50 mH =
Current in the coil, i = A
where
Now,
(a) To calculate the maximum emf:
We know that maximum emf induced in the coil is given by:
For maximum emf, should be maximum, i.e., 1
Now, the magnitude of the maximum emf is given by:
(b) To calculate the maximum average flux,we know that:
(c) To calculate the magnitude of the induced emf at t = 0.0180 s: