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zheka24 [161]
3 years ago
10

How much work would be needed to lift the ball from the 2-m shelf to the 5-m shelf, and how much potential energy would it have

on the 5-m shelf?
Physics
1 answer:
Stells [14]3 years ago
6 0

Answer:

a) 2.94 N

b) 4.90 N

Explanation:

Let us assume that the weight of the ball is 0.98 N

Solution:

a) An object’s gravitational potential energy depends on two factors which are height and its weight (or mass). The equation for gravitational potential energy (PE) is given as:  

Potential energy = weight (w) * height (h)

PE = wh

Potential energy at 2 m shelf = weight * height = 0.98 N * 2 m = 1.96 N

Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N

The work needed to lift the ball from the 2-m shelf to the 5-m shelf = Potential energy at 5 m shelf - Potential energy at 2 m shelf

The work needed to lift the ball from the 2-m shelf to the 5-m shelf = 4.90 N - 1.96 N = 2.94 N

b) Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N

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Tpy6a [65]

Answer:

Part a)

a = 0.056 m/s^2

Part b)

L = 7.85 m

Explanation:

Part a)

Angular speed of the pedal is changing from 60 rpm to 90 rpm in 10 s

so the angular acceleration is given as

\alpha = \frac{\omega_2 - \omega_1}{\Delta t}

so we will have

\alpha = \frac{2\pi(\frac{90}{60}) - 2\pi(\frac{60}{60})}{10}

\alpha = 0.314 rad/s^2

now the tangential acceleration of the pedal is given as

a = r \alpha

a = 0.18 \times 0.314

a = 0.056 m/s^2

Part b)

Total angular displacement made by the sprocket in the interval of 10 s is given as

\theta = \frac{\omega_f + \omega_i}{2} t

\theta = \frac{2\pi (\frac{90}{60}) + 2\pi (\frac{60}{60})}{2}(10)

\theta = 78.5 radian

now length of the chain passing over it is given as

L = R\theta

L = 0.10 \times 78.5

L = 7.85 m

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4 years ago
Technician A says test lights are great for quick tests on non-computerized circuits. Technician B says you can use a test light
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Answer:

that technician A is right

Explanation:

The test lights are generally small bulbs that are turned on by the voltage and current flowing through the circuit in analog circuits, these two values ​​are high and can light the bulb. In digital circuits the current is very small in the order of milliamps, so there is not enough power to turn on these lights.

From the above it is seen that technician A is right

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4 years ago
You are driving a metric car that has a speedometer that displays in meters per second. When you look down at your speedometer,
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A 25 kg mass is accelerated by a force at a rate of 5 m/s2. What is the magnitude of the force that accelerates the man?
svlad2 [7]
Force=mass*acceleration
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3 years ago
Sugar dissolved in water is an example of?
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Answer:

D. Solution

Explanation:

Sugar dissolved in water is an example of solution.

A solution is a homogenous mixture of solutes and solvents.

In a solution the solute particles ae distributed uniformly in the solvents. The solute is the substance and it is the sugar here that is dissolved to make a solution.

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3 years ago
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