Answer:
Step-by-step explanation:
Find the sum of the first 42 terms of the following series, to the nearest integer.
2,7,12
Solution
The sum is given by
SUM_n=n/2*(a_1+a_n)
a_n=a_1+(n-1)d
a_1=2, n=42, d=5
The 42nd term is therefore given by
a_42=2+(42-1)5=207
SUM_42=42/2*(2+207)=21*209=4389
The sum of the first 42 terms of the series, therefore, is 4389
First one is 5/15 next one is 5/5 next one is 15/3 next one is 15/5 I think u know how to simplify so ya
Answer:
D. (4,3)
Step-by-step explanation:
I calculated it logically
This can't be factored with rational numbers.
You use new over old
1.09
_____ then times that by
0.87. 100= 125.287356
Next put that to the nearest 10th which is 130%
