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Zielflug [23.3K]
4 years ago
15

Which quadratic equation is equivalent to (x+2)2+5(x+2)-6=0

Mathematics
1 answer:
professor190 [17]4 years ago
6 0
(x+2)^2+5(x+2)-6=0\\\\x^2+2\cdot x\cdot2+2^2+5\cdot x+5\cdot2-6=0\\\\x^2+4x+4+5x+4-6=0\\\\x^2+9x+2=0
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Plz help.........................
Salsk061 [2.6K]
The second one the are both perfect squares 
3 0
3 years ago
2) (6 pts) A surveyor has taken the measurements shown below. Find the distance<br> across the lake.
katen-ka-za [31]

Answer:

sine rule

Step-by-step explanation:

this can be solved using sine rule

sinA/a=sinnB/b

7 0
3 years ago
How do I solve this problem
Brums [2.3K]

Answer:

a =9

b= 28

Step-by-step explanation:

The parts of the ratio must be equal

5:7:a = 20:b:36

How do we get from 5 to 20

We multiply by 4

So multiply the first by 4

5*4:7*4:a*4 = 20:b:36

Ratio 1

5*4 =20  true

Ratio 2

7*4 =b

28 = b

Ratio 3

4a = 36

Divide by 4

4a/4 = 36/4

a = 9

4 0
3 years ago
The length between (3, 8) and (-2, -4) is ______?
Mumz [18]

Answer:

4,4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
For what values of​ a, m, and b does the function​ f(x) satisfy the hypotheses of the mean value theorem on the interval [0 comm
igomit [66]

Answer:

a = -5

b = -1

m = -1

Step-by-step explanation:

Piecewise function:

f(x)= -5, x=0

f(x)= −x^2+3x+a, 0<x<2

f(x)= mx + b 2≤x≤3

The mean value theorem is applicable if f(x) is continuous on the entire closed interval [0;3] and differentiable on the entire closed interval [0;3].

To satisfied that at x = 0 :

−x^2+3x+a = -5

Then, a = -5

 

Derivative of −x^2+3x-5 is -2x + 3 and derivative of mx + b is m, at x = 2:

-2(2) + 3 = m

-1 = m

Replacing the functions at x = 2 :

−x^2+3x-5 = -x + b

−(2)^2+3*2-5 = -2 + b

-3 + 2 = b

-1 = b

5 0
3 years ago
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